The Mass of the barter and the ball is 3.1kg
Data Given;
- F = 1.1*10^-9N
- r = 0.76m
- G = 6.67*10^-11 m^3 kg^-1 s^-1
Assuming the barter and the ball have equal mass, we can apply gravitational force formula.
<h3>Gravitational Force</h3>
This is product of the mass of the two bodies and divided by the square of their distance apart.
Substituting the values into the formula
From the calculations above, the mass of the barter and the ball is 3.1kg
Learn more on gravitational force here;
brainly.com/question/11359658
In a parallel circuit, the equivalent resistance is the reciprocal of (the sum of the individual reciprocals).
1/R = 1/10 + 1/21 + 1/13
1/R = 0.225 mhos
R = 4.45 ohms
I = V / R
The total current out of the battery is
I = (9v)/(4.45ohms)
I = 2.02 Amperes
As the total current leaves the battery, it splits into 3 paths, and each resistor gets part of it. The 10ohm resistor gets the most current; the 21ohm resistor gets the least current. After flowing through the resistors, the 3 currents join and add up to 2.02 Amperes again, and the same current returns to the battery.
Each resistor has the same 9v of EMF across it.
Since the density of water is 1g/cm^3, The mass of water needed to fill the tank is 150000 grams
Answer:
i Guess 1 or 3
Explanation:
yea 1 or 3 or just guess hard
Answer:
Explanation:
Horizontal displacement
x = 120 t
Vertical position
y = 3610 - 4.9 t²
y = 0 for the ground
0 = 3610 - 4.9 t²
t = 27.14 s
This is the time it will take to reach the ground .
During this period , horizontal displacement
x = 120 x 27.14 m
= 3256.8 m
So packet should be released 3256.8 m before the target.
