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Oliga [24]
3 years ago
5

I do not know where to start.

Physics
1 answer:
irakobra [83]3 years ago
4 0
Underline the words then eliminate the ones that arent part of the problem!
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Both Newton's Law of Universal Gravitation and Coulomb's Law follow the ...
Romashka [77]

Answer:

inverse square relationship

Explanation:

Both the Newton's law of universal gravitation and coulomb's law have their force inversely proportion to the square of the distance between the bodies.

8 0
2 years ago
All of the following show friction as a useful force, except _____.
prohojiy [21]

Answer: having to push a rough and heavy box across the floor to move it

Explanation:

The Friction force is any force that is in opposite direction of the motion of an object or fluid due to the contact of this object or fluid with other bodies.

In this sense, there are different types of friction force thath are useful in different situations:

-The <u>Static friction force</u> prevents surfaces from slipping across each other. For example, the friction between your feet and the floor keeping you from slipping.

-The <u>kinetic friction force</u> as the force that helps the tires in a moving vehicle to slow down and stop when necessary.

However, if you want to push a heavy box across the floor to move it, the friction force will not be useful at all.

6 0
3 years ago
Read 2 more answers
The moon orbits the earth at a distance of 3.85 x 10^8 m. Assume that this distance is between the centers of the earth and the
Inga [223]

Answer:

27.5 days

0.92 month

Explanation:

r = radius of the orbit of moon around the earth = 3.85\times10^{8} m

M = Mass of earth = 5.98\times10^{24} m

T = Time period of moon's motion

According to Kepler's third law, Time period is related to radius of orbit as

T^{2} = \frac{4\pi ^{2} r^{3}  }{GM}

inserting the values, we get

T^{2} = \frac{4(3.14)^{2} (3.85\times10^{8})^{3}  }{(6.67\times10^{-11})(5.98\times10^{24})}\\T = 2.3754\times10^{6} sec

we know that

1 day = 24 hours = 24 x 3600 sec = 86400 s

T = 2.3754\times10^{6} sec \frac{1 day}{86400 sec} \\T = 27.5 days

1 month = 30 days

T = 27.5 days \frac{1 month}{30 days} \\T = 0.92 month

6 0
3 years ago
A rock is dropped from a vertical cliff. The rock takes 6.00 s to reach the ground below the cliff. What is the height of the cl
Lana71 [14]

Answer:

180 m

Explanation:

The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation

h=\frac{1}{2}gt^2

where

g = 10 m/s^2 is the acceleration due to gravity

t = 6.00 s is the time of the fall

Substituting these data, we find the height of the cliff:

h=\frac{1}{2}(10 m/s^2)(6.00 s)^2=180 m

4 0
3 years ago
A bicyclist was moving at a rate of 3 m/s, and then sped up to 4 m/s. If the cyclist has a mass of 100 kg, how much work was nee
kotegsom [21]

Answer:

i got b but urs is a little different tell me if right

Explanation:

i go 100 on my test

7 0
2 years ago
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