Answer:
v₂ = - 1.29 m / s
, K₁ / Em = 0.996
, K₂ / Em = 0.004
Explanation:
This is an exercise for the moment, where the system is formed by the shotgun, the man arm and the bullet, in this case the forces are internal therefore the moment is conserved
Initial. Before shooting
p₀ = 0
Final. After shooting
= m v₁ + M v₂
Where index 1 is for the bullet and index 2 for the shotgun, arm and man set
The mass of the bullet is m = 0.04 kg
The mass of the set M = 3.0 + 12.5 = 15.5 kg
p₀ =
0 = m v₁ + M v₂
v₂ = - m / M v₁
v₂ = - 0.04 / 15.5 400
v₂ = - 1.29 m / s
The mechanical energy is equal to the kinetic energy, let's calculate the energy for each of the two elements
K₁ = ½ m v₁²
K₁ = 1/2 0.04 400²
K₁ = 3200 J
K₂ = ½ M v₂²
K₂ = ½ 15.5 1.29²
K₂ = 12.90 J
The total energy of the system is the sum of the energy of each component
Em = K₁ + K₂
Em = 3200 + 12.90
Em = 3212.9 J
The fraction of transmitted energy is
To the bullet
K₁ / Em = 3200 / 3212.9
K₁ / Em = 0.996
To the system
K₂ / Em = 12.9 / 3212.9
K₂ / Em = 0.004
Answer: kinetic energy
Explanation:
Kinetic energy is the form of energy related to the motion of an object. The kinetic energy of an object is given by:
where m is the mass of the object and v its speed. Therefore, any object in motion has kinetic energy: in this case, the bowling ball is in motion before the collision, so during the collision it transfers its kinetic energy to the pins.
Answer:
Also 0
Explanation:
Since average speed of an object is that object's displacement over a unit of time, when an average speed is 0, its displacement over a unit of time must also be 0. When an average speed is not 0, then its displacement over a unit of time is also not 0 for that interval.
8 tablespoons of water.
2 x 4 = 8
I hope this helps :)