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taurus [48]
3 years ago
9

What did the Curies demonstrate by studying pitchblende?

Chemistry
2 answers:
mylen [45]3 years ago
5 0

Answer:

a on edge

Explanation:

Mekhanik [1.2K]3 years ago
3 0

Answer:

A- Uranium is not only the radioactive element

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An electromagnetic wave that has a higher frequency than ultraviolet light will have ____ than the ultraviolet light.
8_murik_8 [283]
C)shorter wavelength and higher energy
frequency is inversely proportional to wavelength
frequency is directly proportional to Energy
5 0
2 years ago
What's lithium scientific name?
disa [49]
Well it's an alkali metal if that's what you're asking<span />
7 0
3 years ago
At one point in the Bike Trip described in the passage, you traveled 1 kilometer in 0.1 hours. What was your speed during that t
stealth61 [152]

Answer:

v = 10 km/h

Explanation:

Step 1: Given data

  • Distance traveled in the Bike Trip (d): 1 km
  • Time elapsed in the Bike Trip (t): 0.1 h

Step 2: Calculate the speed in the Bike Trip

The speed (v) is equal to the distance traveled divided by the time elapsed. We will use the following mathematical expression.

v = d/t

v = 1 km/0.1 h

v = 10 km/h

The speed is 10 kilometers per hour.

7 0
3 years ago
How many atoms of both elements are there in this molecule: 3N205; O 3 Nitrogen and 15 Oxygen 6 Nitrogen and 5 Oxygen KD 2 Nitro
abruzzese [7]

Answer:

Explanation:

oxygen is a 15 and nitrogen science chemistry i'm guessing

6 0
3 years ago
Calculate the number of moles of caco3 (calcium carbonate, or limestone) in a 20.0g sample of this substance
Brrunno [24]
First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.

     molar mass of CaCO₃ = (1 mol Ca)(40 g Ca/mol Ca) + (1 mol C)(12 g of C/1 mol of C) + (3 mols of O)(16 g O/1 mol O) = 100 g/mol of CaCO₃

Then, divide the given amount of substance by the calculated molar mass.
            number of moles = (20 g)(1 mol of CaCO₃/100 g)
             number of moles = 0.2 moles of CaCO₃

<em>Answer: 0.2 moles</em>
6 0
3 years ago
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