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taurus [48]
3 years ago
9

What did the Curies demonstrate by studying pitchblende?

Chemistry
2 answers:
mylen [45]3 years ago
5 0

Answer:

a on edge

Explanation:

Mekhanik [1.2K]3 years ago
3 0

Answer:

A- Uranium is not only the radioactive element

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Calculate the density in g/ml of 2.0 L of gasoline that weighs 1.32 kg
sveta [45]

Answer: 0.66 g/mL

Explanation: The formula for density is d= m/v where m=mass and v=volume.

The mass was given in the problem, m= 1.32kg

The volume was also given in the problem, v= 2.0L

d= m/v ---> d= 1.32kg/2.0L ---> d=0.66kg/L

The problem calls for the answer to be written in g/mL, so we must convert the units. 1 kg contains 1000g and 1 L contains 1000 mL.

1000g/1000mL = 1 so the units change but the 0.66 does not. Therefore, your answer is 0.66g/mL (Two significant figures because 2.0 only has 2 significant figures).

4 0
2 years ago
An electrochemical cell is made up of an Zn2+/Zn half-cell and an Ag+/Ag half-cell. If the mass deposited at the silver electrod
Leokris [45]

Answer:

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7 0
3 years ago
What happens to water when it changes to ice?
mariarad [96]
Density decreases that's why ice floats on water because it's less dense than water.

5 0
3 years ago
Read 2 more answers
At 35°C, Kc = 1.6 multiplied by10-5 for the following reaction
Brums [2.3K]

Answer : The equilibrium concentrations of all species NO,Cl_2\text{ and }NOCl are, 0.05 M, 0.043 M and 0.975 M respectively.

Explanation : Given,

Moles of  NO = 2 mole

Moles of  Cl_2 = 1 mole

Volume of solution = 1 L

Initial concentration of NO = 2 M

Initial concentration of Cl_2 = 1 M

The given balanced equilibrium reaction is,

                            2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

Initial conc.          2 M            1 M            0

At eqm. conc.    (2-2x) M   (1-x) M         (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NOCl]^2}{[NO]^2[Cl_2]}

The K_c for reverse reaction = \frac{1}{1.6\times 10^{-5}}

Now put all the given values in this expression, we get :

\frac{1}{1.6\times 10^{-5}}=\frac{(2x)^2}{(2-2x)^2\times (1-x)}

By solving the term 'x', we get :

x = 0.975

Thus, the concentrations of NO,Cl_2\text{ and }NOCl at equilibrium are :

Concentration of NO = (2-2x) M  = (2 - 2 × 0.975) M = 0.05 M

Concentration of Cl_2 = (1-x) M = 1 - 0.975 = 0.043 M

Concentration of NOCl = x M = 0.975 M

Therefore, the equilibrium concentrations of all species NO,Cl_2\text{ and }NOCl are, 0.05 M, 0.043 M and 0.975 M respectively.

6 0
3 years ago
How is good at electron configurations in chemistry?
Paha777 [63]

Try to understand all the rules and laws like:

Aufbau Principle

Hund's rule

Pauli exclusion principle...

Then, you should understand the way in which you can fill the electrons in the orbitals!!

8 0
3 years ago
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