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OleMash [197]
3 years ago
10

Why does fluorine have a higher ionization energy than iodine?

Chemistry
1 answer:
Minchanka [31]3 years ago
7 0
Fluorine has a higher ionization energy because it is in a lower energy level and does not receive the same intensity of shielding as Iodine. Thus Fluorine has a stronger nuclear force on the surrounding electrons and require more energy to remove electrons.
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What is the mass of an atom with seven protons, seven neutrons, and eight electrons?
belka [17]

Answer:

14

Explanation:

mass number = protons + neutrons

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3 years ago
Is this equation balanced?<br><br>nh4oh+hc2h3o2=nh4c2h3o2+h2o​
Usimov [2.4K]

Answer:

It IS balanced

Explanation:

3 0
3 years ago
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What is the solution's freezing point: 15 g of CH4N2O (Molar mass = 60.055 g/mol) in 200. g of H2O? (Kf = 1.86 (°C·kg)/mol)
AURORKA [14]

Ok to answer this question we firsst need to fin the number of mol of Urea (CH4N2O). to do this we simply :

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therefore 200g of water contain 0.25mol

the next step is to determine the malality of our solution in 200g of water, to do this we say:

200 g = 1Kg/1000g = 0.2kg

therefor 0.25mol/0.2Kg = 1.25mol/kg

and from the equation:

we know that i = 1

we are given Kf

b is the molality that we just calculated

therefore;

the solutions freezing point is -2.325°C

8 0
1 year ago
A police car is approaching the corner. Explain what happens to the frequency of sound as it draws closer. What will you hear?
barxatty [35]
The frequency stays the same it just gets louder
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3 years ago
Which of the following is a completely elastic collision? A. a ball rebounds against a wall, reversing its direction, but at onl
Dmitry_Shevchenko [17]

Answer:

Answer E.

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We can go through each answer choice:

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B. A collision involving sticking is an example of a perfectly INELASTIC collision. This is NOT an elastic collision.

C. A reduced speed indicates that there is a loss of kinetic energy. This is NOT elastic.

D. The balls traveling at half the speed after the collision indicates a loss of kinetic energy, making this collision NOT elastic.

E. This collision indicates an exchange of velocities, characteristic of an elastic collision. We can prove this:

Let:

m = mass of each ball

v = velocity

We have the initial kinetic energy as:

KE = \frac{1}{2}mv^2 + 0 = \frac{1}{2}mv^2KE=21mv2+0=21mv2

And the final as:

KE = 0 + \frac{1}{2}mv^2 = \frac{1}{2}mv^2KE=0+21mv2=21mv2

5 0
2 years ago
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