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fgiga [73]
3 years ago
13

I tried finding the answer to this time and time again. I cannot find it. I hope someone can help me. What does photochemical sm

og react with?
Chemistry
1 answer:
dimulka [17.4K]3 years ago
5 0

A chemical reaction between solar ultraviolet radiation and an atmosphere polluted with hydrocarbons and oxides of nitrogen causes photochemical smog. ... Smog can happen both during the day and at night, but photochemical smog only happens in the presence of sunlight.

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What is the concentration of a solution containing 0.32 moles of NaCl in 3.4 liters?
dsp73
Get the molarity we need to divide the number of moles of NaCl by the volume of the solution. So, 0.32 moles NaCl divided by 3.4 L, and that gives 0.094 M NaCl.
5 0
2 years ago
Read 2 more answers
Read the following paragraph from the section "Dreaming Of A World Deep Below."
LiRa [457]

Answer:

B

Explanation:

The interior planet has fascinated a lot of people so a lot of theories have been made about what's in there.

6 0
2 years ago
Why is physical exercise often suggested if you experience an abundance of stress?
scoray [572]

Answer:

good question

Explanation:

probably because people like to say they know things and help people with "there stress" and think that there helping them but in reality there making it where they have more :)

4 0
3 years ago
How many molecules are present in 2 H₂ SO4​
fomenos

Answer:

in H2So4 splits in 2 H+ and a

so42 -particle=3particle per mole.So2

moles H2So4 will result in 3*2=6moles

of molecules.

5 0
3 years ago
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An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre
Wewaii [24]
Chemical reaction: Ba(NO₃)₂ + H₂SO₄ → BaSO₄ + 2HNO₃.
V(H₂SO₄) = 250 mL ÷ 1000 mL/L = 0,25 L.
m(BaSO₄) = 0,55 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,55 g ÷ 233,38 g/mol.
n(BaSO₄) = 0,00235 mol.
From chemical reaction: n(BaSO₄) : n(Ba(NO₃)₂) = 1 : 1.
n(Ba(NO₃)₂) = 0,00235 mol.
c(Ba(NO₃)₂) = n(Ba(NO₃)₂) ÷ V.
c(Ba(NO₃)₂) = 0,00235 mol ÷ 0,25 L.
c(Ba(NO₃)₂) = 0,0095 mol/L.
7 0
3 years ago
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