I tried finding the answer to this time and time again. I cannot find it. I hope someone can help me. What does photochemical sm
1 answer:
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Answer:
Molar mass of solute: 300g/mol
Explanation:
<em>Vapor pressure of pure benzene: 0.930 atm</em>
<em>Assuming you dissolve 10.0 g of the non-volatile solute in 78.11g of benzene and vapour pressure of solution was found to be 0.900atm</em>
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It is possible to answer this question based on Raoult's law that states vapor pressure of an ideal solution is equal to mole fraction of the solvent multiplied to pressure of pure solvent:
Moles in 78.11g of benzene are:
78.11g benzene × (1mol / 78.11g) = <em>1 mol benzene</em>
Now, mole fraction replacing in Raoult's law is:
0.900atm / 0.930atm = <em>0.9677 = moles solvent / total moles</em>.
As mole of solvent is 1:
0.9677× total moles = 1 mole benzene.
Total moles:
1.033 total moles. Moles of solute are:
1.033 moles - 1.000 moles = <em>0.0333 moles</em>.
As molar mass is the mass of a substance in 1 mole. Molar mass of the solute is:
10.0g / 0.033moles = <em>300g/mol</em>
Answer:
no. of water molecules associated to each molecule of = 4
Explanation:
Mass of before heating = 19.8 g
Mass of after heating = 12.6 g
Difference in mass of before and after heating
= 19.8 - 12.6 = 7.2 g
Difference in mass corresponds to mass of water driven out.
Molar mass of water = 18 g/mol
No. of moles of water =
Mass of obtained after heating is mass of anhydrous
.
Mass of anhydrous = 12.6 g
Molar mass of = 125.9 g/mol
No. of mol of anhydrous =
so,
0.1 mol of have 0.4 mol of water
1 mol of will have =
Hence, no. of water molecules associated to each molecule of = 4