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DerKrebs [107]
2 years ago
7

What do oxidation reactions produce during the electrolysis of water?

Chemistry
2 answers:
jok3333 [9.3K]2 years ago
8 0
Hydrogen gas, oxygen gas and water

4H2O (l) ---> 2H2O (l) + O2 (g) + 2H2 (g)
klemol [59]2 years ago
3 0

Answer : Oxidation reaction produces oxygen and water molecule during electrolysis of water.

Explanation:

Electrolysis : It is a type of process in which the chemical decomposition produced by passing an electric current through the solution that containing the ions.

Electrolysis of water : It is basically the decomposition of water into oxygen and hydrogen gas through a process of electric current.

Oxidation reaction is defined as the reaction in which a substance looses its electron to attain stability.

The chemical reactions during electrolysis of water are:

At cathode:  2H_2O+2e^-\rightarrow H_2+2OH^-

At anode:  2OH^-\rightarrow \frac{1}{2}O_2+H_2O+2e^-

Overall reaction: H_2O\rightarrow H_2+\frac{1}{2}O_2

Oxidation reaction occurs at anode.

Hence, oxidation reaction produces oxygen and water molecule during electrolysis of water.

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What is the theoretical yield of methanol (CH3OH) when 12.0 grams of H2 is mixed with 74.5 grams of CO? CO + 2H2 CH3OH
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1) We need to convert 12.0 g of H2 into moles of H2, and <span> 74.5 grams of CO into moles of CO
</span><span>Molar mass of H2:    M(H2) = 2*1.0= 2.0 g/mol
Molar mass of CO:   M(CO) = 12.0 +16.0 = 28.0 g/mol

</span>12.0 g  H2 * 1 mol/2.0 g = 6.0 mol H2
74.5 g CO * 1 mol/28.0 g = 2.66 mol CO

<span>2) Now we can use reaction to find out what substance will react completely, and what will be leftover. 

                                  CO       +         2H2   ------->      CH3OH  
                                 1 mol              2 mol
given                        2.66 mol          6 mol (excess)

How much
we need  CO?           3 mol              6 mol

We see that H2 will be leftover, because for 6 moles H2  we need 3 moles CO, but we have only 2.66 mol  CO.
So, CO will react completely, and we are going to use CO to find  the mass of CH3OH.

3)                              </span>CO       +         2H2   ------->      CH3OH  
                                 1 mol                                        1 mol
                                2.66 mol                                    2.66 mol

4) We have 2.66 mol CH3OH
Molar mass CH3OH : M(CH3OH) = 12.0 +  4*1.0 + 16.0 = 32.0 g/mol

2.66 mol CH3OH * 32.0 g CH3OH/ 1 mol CH3OH =  85.12 g CH3OH
<span>
Answer is </span>D) 85.12 grams.
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2 years ago
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