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DerKrebs [107]
3 years ago
7

What do oxidation reactions produce during the electrolysis of water?

Chemistry
2 answers:
jok3333 [9.3K]3 years ago
8 0
Hydrogen gas, oxygen gas and water

4H2O (l) ---> 2H2O (l) + O2 (g) + 2H2 (g)
klemol [59]3 years ago
3 0

Answer : Oxidation reaction produces oxygen and water molecule during electrolysis of water.

Explanation:

Electrolysis : It is a type of process in which the chemical decomposition produced by passing an electric current through the solution that containing the ions.

Electrolysis of water : It is basically the decomposition of water into oxygen and hydrogen gas through a process of electric current.

Oxidation reaction is defined as the reaction in which a substance looses its electron to attain stability.

The chemical reactions during electrolysis of water are:

At cathode:  2H_2O+2e^-\rightarrow H_2+2OH^-

At anode:  2OH^-\rightarrow \frac{1}{2}O_2+H_2O+2e^-

Overall reaction: H_2O\rightarrow H_2+\frac{1}{2}O_2

Oxidation reaction occurs at anode.

Hence, oxidation reaction produces oxygen and water molecule during electrolysis of water.

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8.03 Solutions Lab Report<br> Does anyone have a PDF or Document of FLVS 8.03 Solutions Lab
GarryVolchara [31]

8.03 solutions report is described below.

Explanation:

8.03 Solutions Lab Report

In this laboratory activity, you will investigate how temperature, agitation, particle size, and dilution affect the taste of a drink. Fill in each section of this lab report and submit it and your pre-lab answers to your instructor for grading.  

Pre-lab Questions:

In this lab, you will make fruit drinks with powdered drink mix. Complete the pre-lab questions to get the values you need for your drink solutions.  

Calculate the molar mass of powered fruit drink mix, made from sucrose (C12H22O11).

Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL.

7 0
3 years ago
Read 2 more answers
Help needed Assignment is due Justify that H2SO4 is Arrhenius acid and KOH is Arrhenius base.
irakobra [83]

Answer:

<u><em>Arrhenius Acid:</em></u>

According to Arrhenius concept, Acids are proton donors.

Since H₂SO₄ have a proton (H⁺ ion) and it can donate it to be made a sulphate ion, So it is an Arrhenius acid.

See the following reaction =>

<u><em>H₂SO₄ + H₂O => HSO₄ + H₃O⁺</em></u>

<u><em>Arrhenius Base:</em></u>

An Arrhenius base is a a proton acceptor.

KOH accepts the proton to to made to KOH₂ and a proton acceptor.

See the following reaction =>

<u><em>KOH + H₂o => KOH₂ + OH⁻</em></u>

<u><em></em></u>

6 0
3 years ago
the atomic number of an element x is 14 and its relative atomic mass is 28 write the electronic distribution in an atom of x​
AlekseyPX

Answer:

the electronic distribution in an atom of x is 14

3 0
2 years ago
34 POINTS<br><br> Why is managing stress an important part of staying healthy
MrRa [10]
Managing stress is important to your health because stress can give you many illnesses. Reducing stress improves your mood and boosts your immune system. Stress can give you rapid heart rates and high blood pressure.
7 0
3 years ago
Suppose you have been given the task of distilling a mixture of hexane + toluene. Pure hexane has a refractive index of 1.375 an
miv72 [106K]

Explanation:

The given data is as follows.

         Refractive index of mixture = 1.456

        Refractive index of hexane = 1.375

        Refractive index of toulene = 1.497

Let mole fraction of hexane = x_{1}

and, mole fraction of toulene = x_{2}

Also,        x_{1} + x_{2} = 1

or,            x_{1} = 1 - x_{2}

Hence, calculate the mole fraction of hexane as follows.

        refractive index mixture= mole fraction hexane × ref index hexane + mole fraction toluene × ref index toluene.

              1.456 = (1 - x_{2}) \times 1.375 + x_{2} \times 1.497

               1.456 = 1.375 - 1.375x_{2} + 1.497x_{2}

               0.081 = 0.122x_{2}

                   x_{2} = \frac{0.081}{0.122}

                                = 0.66

Since,     x_{1} = 1 - x_{2}

                          = 1 - 0.66

                          = 0.34

Thus, we can conclude that mole fraction of hexane in your sample is 0.34.        

3 0
3 years ago
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