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sashaice [31]
3 years ago
12

What motivates the squire in lines 85- 90?

Physics
1 answer:
just olya [345]3 years ago
5 0
<span>Answer: If you mean the Knight in the prologue, the man traveling with his son (the Squire) and a Yeoman, he is traveling to Canterbury to give thanks for his safe return from the wars in the Baltic. We're told that he has never been known to speak unkindly to anyone, a fact that sums up his chivalrous upbringing. Evidently he feels strongly motivated to live by a code of high standards and refined behavior.</span>
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When a beam of charged particles moves through a magnetic field, what is the evidence that particles in the beam have momentum g
Vsevolod [243]

The charged particles are often deflated in a magnetic field.

<h3>What is a magnetic field?</h3>

The term charge refers to a positive or negative entity. The can be created when a charge is made to pass through a conductor in a magnetic field.

A magnetic field is created when we have a north pole and a south pole. The charged particles could be made to pass through the electric field and when that happens, we can see a pattern a shown in the image attached.

Thus, we can see that the charged particles are often deflated in a magnetic field.

Learn more about magnetic field:brainly.com/question/23096032

#SPJ1

4 0
1 year ago
Carbonic acid _____.
artcher [175]
Dissolves limestone and other rocks.

3 0
3 years ago
Read 2 more answers
Rotation of the lever OA is controlled by the motion of the contacting circular disk of radius r = 300 mm whose center is given
sergiy2304 [10]

Answer:

The angular velocity is

5.64rad/s

Explanation:

This problem bothers on curvilinear motion

The angular velocity is defined as the rate of change of angular displacement it is expressed in rad/s

We know that the velocity v is given as

v= ωr

Where ω is the angular velocity

r is 300mm to meter = 0.3m

the radius of the circle

described by the level

v=1.64m/s

Making ω subject of the formula and solving we have

ω=v/r

ω=1.64/0.3

ω=5.46 rad/s

3 0
3 years ago
A locomotive accelerates a 25-car train along a level track. Every car has a mass of 7.7 ✕ 104 kg and is subject to a friction f
MaRussiya [10]

To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.

In this way,

The total mass of the cars would be,

m_T = 25(7.7*10^4)Kg

m_T = 1.925*10^6Kg

Therefore the friction force at 29Km / h would be,

f=250v

f= 250*29Km/h

f = 250*29*(\frac{1000m}{1km})(\frac{1h}{3600s})

f = 2013.889N

In this way the tension exerts between first car and locomotive is,

T=m_Ta+f

T=(1.925*10^6)(0.2)+2013.889

T= 3.8701*10^5N

Therefore the tension in the coupling between the car and the locomotive is 3.87*10^5N

6 0
3 years ago
Time (s)
olya-2409 [2.1K]

The moon orbiting the Earth

Explanation:

The motion of the moon orbiting the earth is a circular motion. Circular motion is simply the motion of an object in circle at constant speed.

  • A cannonball flying from a cannon is a projectile motion and not a circular motion.
  • A car moving along a straight track is a linear/translational motion.
  • Pendulum of a grandfather clock is a simple harmonic motion.

Learn more:

Circular motion brainly.com/question/2562955

#learnwithBrainly

7 0
3 years ago
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