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3 years ago

If you can answer all of this then your a legend (I'm giving you all my points)

Physics

1 answer:

navik [9.2K]3 years ago

3 0

Answer:

1. B

2. B

3. D

4. A

Hope this was correct! A lot of the answers are already in the article itself and the wording is just different. I suggest now that for information retainment, you read the article again with the correct points in mind and see if you can spot the points where the answers are stated!

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you stand on a straight desert road at night and observe a vehicle approaching. this vehicle is equipped with two small headligh

inysia [295]

Answer:

The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km

Explanation:

Given:

d = distance = 0.679 m

λ = wavelength of the light = 537 nm = 537x10⁻⁹m

dp = pupil diameter = 4.81 mm = 0.00481 m

Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?

For the separation of the peak from the central maximum it is:

$sin\theta =\frac{\lambda }{d_{p} } =\frac{537x10^{-9} }{0.00481} =1.116x10^{-4}$

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye

$d_{x} =\frac{d}{sin\theta } =\frac{0.679}{1.116x10^{-4} } =6.084x10^{3} m=6.084km$

7 0

4 years ago

Inhaling moves the diapragm (blank) and expand the (blank)

Anastaziya [24]

Inhaling moves the diaphragm CONTRACTS and expand the LUNGS.

7 0

2 years ago

a nonrelativistic proton is confined to a length of 2.0 pm on the x-axis. what is the kinetic energy of the proton if its speed

Elina [12.6K]

Answer:

K = 1.29eV

Explanation:

In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:

$\Delta x \Delta p\geq \frac{h}{4\pi}$ (1)

Δx : uncertainty of position = 2.0pm = 2.0*10^-12m

Δp: uncertainty of momentum = ?

h: Planck's constant = 6.626*10^-34 J.s

You calculate the minimum possible value of Δp from the equation (1):

$\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}$

The minimum kinetic energy is calculated by using the following formula:

$k=\frac{(\Delta p)^2}{2m}$ (2)

m: mass of the proton = 1.67*10^{-27}kg

$k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J$

in eV you have:

$2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV$

The kinetic energy of the proton is 1.29eV

7 0

3 years ago

The mass of the motorbike and rider is 286 kg. Calculate the acceleration of the motorbike at this moment in time.

Aleks04 [339]

Answer:

$a=4.03\ m/s^2$

Explanation:

Given that,

The mass of the motorbike and rider is 286 kg.

We need to find the acceleration of the motorbike at this moment in time.

Net force acting on the bike is given by :

F = 2000 N - 845 N = 1155 N

Let a be the acceleration of the motorbike. So,

$a=\dfrac{F}{m}\\\\a=\dfrac{1155}{286}\\\\a=4.03\ m/s^2$

So, the acceleration of the motorbike is $4.03\ m/s^2$ .

7 0

3 years ago

What are the precautions to be taken while performing a rectangular glass prism experiment

omeli [17]

Answer:

PRECAUTIONS

-The refracting faces of the glass prism should be smooth, transparent and without any air bubble or broken edge. ...

-Use a sharp pencil to draw boundary of the prism and rays of light.

-The alpins should have sharp tip and should be fixed exactly vertical to the plane of the paper.

Explanation:

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3 0

3 years ago