Which of the following describe advantages of using radio waves over other electromagnetic waves to transmit information to Eart
h? Select ALL that apply.
A
Radio waves travel faster.
B
Radio waves take less energy to produce.
C
Radio waves transmit more types of information.
D
Radio waves have a lower frequency, which makes them safer for humans.
E
Radio waves have higher energy, which makes their signal easier to capture.
A
Radio waves travel faster.
B
Radio waves take less energy to produce.
C
Radio waves transmit more types of information.
D
Radio waves have a lower frequency, which makes them safer for humans.
E
Radio waves have higher energy, which makes their signal easier to capture.
1 answer:
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The angular velocity depends on the length of the orbit and the orbital
speed of the telescope.
Response:
First question:
- The angular velocity of the telescope is approximately <u>0.199 rad/s</u>
Second question:
- The telescope should accelerates away by approximately F = <u>0.0005·m </u>
Third question:
- <u>The pulling force between the Earth and the satellite</u>
The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun
The orbital velocity of the telescope = The Earth's orbital velocity
First question:
The orbital velocity of the Earth = 29.8 km/s
The distance between the Earth and the Sun = 148.27 million km
The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77
Radius of the orbit, r = 149.77 million kilometer from the Sun
The length of the orbit of the James Webb telescope = 2 × π × r
Which gives;
r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers
Therefore;
- The angular velocity of the telescope, ω ≈ <u>0.199 rad/s</u>
Second question:
Centrifugal force force, = m·ω²·r
Which gives;
Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²
Mass of the Sun = 1.989 × 10³⁰ kg
Which gives;
Which gives;
<
, therefore, the James Webb telescope has to accelerate away from the Sun
F = -
The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ <u>0.0005·m (away from the Sun)</u>
Third part:
Other forces include;
- <u>The force of attraction between the Earth and the telescope </u>which can contribute to the the telescope having a stable orbit at the given speed.
Learn more about orbital motion here:
<u>Answer:</u> The specific heat of ice is 2.11 J/g°C
<u>Explanation:</u>
When ice is mixed with water, the amount of heat released by water will be equal to the amount of heat absorbed by ice.
The equation used to calculate heat released or absorbed follows:
......(1)
where,
q = heat absorbed or released
= mass of ice = 12.5 g
= mass of water = 85.0 g
= final temperature = 22.24°C
= initial temperature of ice = -15.00°C
= initial temperature of water = 25.00°C
= specific heat of ice = ?
= specific heat of water = 4.186 J/g°C
Putting values in equation 1, we get:
Hence, the specific heat of ice is 2.11 J/g°C