The LCD is x^2+3x+2 = (x+2)(x+1)
The goal is to get each fraction to have the denominator be equal to the LCD
Afterward we can add the fractions
x/(x^2+3x+2) + 3/(x+1)
x/((x+2)(x+1)) + 3/(x+1)
x/((x+2)(x+1)) + (3(x+2))/((x+2)(x+1))
(x+3(x+2))/((x+2)(x+1))
(x+3x+6)/(x^2+3x+2)
(4x+6)/(x^2+3x+2)
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Final Answer: 4x+6
Note: you can factor 4x+6 to get 2(2x+3)
Answer:
9
Step-by-step explanation:
First off you need to find the interval that four falls in.
Four is not less than three so you can rule out the first one, four is not greater than 10 so you can rule out the last one. But four is greater than three and less than ten, so it falls in the second interval.
So, now you can substitute four in for x for the second equation
4^2-7
16-7
=9
By determining the length of TV using TV^2=15^2+10^2-2(15)(10)cos80, and then determining the value of x using 15^2=TV^2+10^2-2(TV)(10)cosx.
B. 16 I hope, it’s correct answer
