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2 years ago

Please help me with this question my sister needs help and I'm to busy

Mathematics

2 answers:

GuDViN [60]2 years ago

7 0

Answer:

1/4

Step-by-step explanation:

because when you take it from where the 10 and 40 meet to where the 50 adn 50 meet it is over 1 and up 4 which is your fraction. 1/4

RoseWind [281]2 years ago

7 0

Answer:

Step-by-step explanation:

When trying to determine slope from a graph, it is useful to choose points on the graph where the line crosses grid intersections. For this graph, two such points are ...

(x, y) = (40, 10) and (50, 50)

The "rise" between these two points is the difference of their y-coordinates: 50 -10 = 40.

The "run" between these two points is the difference of their x-coordinates: 50 -40 = 10

The slope of the line is the ratio of "rise" to "run":

m = rise/run = 40/10 = 4

The slope of the line is 4.

<em>Additional comment</em>

This graph has scales that are 10 units between grid lines in both the x- and y-directions. This means you can also find the slope by counting grid squares. The points above differ by 4 grid squares in the vertical direction, and 1 grid square in the horizontal direction. Using grid square counts instead of coordinate value differences, we have ...

m = rise/run = 4/1 = 4

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John made a small rectangular table for his workroom. If the sides of the table are 32 inches and 26 inches, what should the tab

matrenka [14]

Answer:

The table should measure diagonally about 41.23 inches.

Step-by-step explanation:

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$a^{2}$ + $b^{2}$ = $c^{2}$

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Read 2 more answers

Distance between parallel lines y=3x+10 and y=3x-20

Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).

2. Use formula $d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}$ to find the distance from point $(x_0,y_0)$ to the line Ax+By+C=0.

The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

$d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}$ .

3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.

Answer: $d=3\sqrt{10}$ .