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2 years ago

Please help me with this question my sister needs help and I'm to busy

Mathematics

2 answers:

GuDViN [60]2 years ago

7 0

Answer:

1/4

Step-by-step explanation:

because when you take it from where the 10 and 40 meet to where the 50 adn 50 meet it is over 1 and up 4 which is your fraction. 1/4

RoseWind [281]2 years ago

7 0

Answer:

Step-by-step explanation:

When trying to determine slope from a graph, it is useful to choose points on the graph where the line crosses grid intersections. For this graph, two such points are ...

(x, y) = (40, 10) and (50, 50)

The "rise" between these two points is the difference of their y-coordinates: 50 -10 = 40.

The "run" between these two points is the difference of their x-coordinates: 50 -40 = 10

The slope of the line is the ratio of "rise" to "run":

m = rise/run = 40/10 = 4

The slope of the line is 4.

<em>Additional comment</em>

This graph has scales that are 10 units between grid lines in both the x- and y-directions. This means you can also find the slope by counting grid squares. The points above differ by 4 grid squares in the vertical direction, and 1 grid square in the horizontal direction. Using grid square counts instead of coordinate value differences, we have ...

m = rise/run = 4/1 = 4

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PLEASE HELP!!! WILL GIVE BRAINLIEST!!!

777dan777 [17]

Answer: (2,2) and (-5,16)

Step-by-step explanation:

Here we have both Line (Linear Function) and Parabola (Quadratic Function)

So I am gonna write these equations here,

$y=x^2+x-4\\y=-2x+6$

The first equation has Parabola graph (Since it's second degree.)

and the second equation has line graph.

To find the intersection, you have to substitute either -2x+6 in first equation (Quadratic) or x^2+x-4 in second equation (Linear)

For me, I am going to substitute x^2+x-4 in y=-2x+6.

$x^2+x-4=-2x+6$

Now solve the equation and find the value of x.

Since it's Quadratic Equation (Because there's x^2) I'd move -2x+6 to the left side.

$x^2+x-4+2x-6=0$ Finish things here (Subtract and Addition)

$x^2+3x-10=0$ What two numbers multiply to 10? Find the factors of 10, that are [1 and 10] and [2 and 5]

Now think about it, do you think that if 1 and 10 subtract or even addition, do you think that it'd be 3? No, of course not.

So 2 and 5 is right.

$(x-2)(x+5)=0$ (5-2 = 3) and (5*(-2) = -10)

Then we get both x, $x=2,-5$

However, this is not it. You have to substitute both x in Linear Equation.

Substitute x = 2 in y=-2x+6

$y=-2(2)+6\\y=-4+6\\y=2$

Order = $(2,2)$

Then substitute x = -5 in y=-2x+6

$y=-2(-5)+6\\y=10+6\\y=16$

Order = $(-5,16)$

So the intersections are both (2,2) and (-5,16) as shown in graph below.

4 0

3 years ago

Physics

Andrej [43]

Answer:

a) Josef jogging from A to B;

i. speed = 2 m/s

ii. velocity = 2m/s

a) a) Josef jogging from A to C;

speed = 1.9 m/s

ii. velocity = 2.2 m/s

Step-by-step explanation:

One major difference between speed and velocity is that speed is a scalar quantity, while velocity is a vector quantity.

a) Josef jogging from A to B;

distance = 300 m

time = 2.5 seconds = 150 seconds

i. his average speed = $\frac{distance}{time}$

= $\frac{300}{150}$

= 2 m/s

ii. his average velocity = $\frac{displacement}{time}$

= $\frac{300}{150}$

= 2 m/s

b) Josef jogging from A to C,

distance = 300 + 100 = 400 m

time = 2.5 + 1 = 3.5 minutes

= 210 seconds

i. his average speed = $\frac{distance}{time}$

= $\frac{400}{210}$

= 1.9 m/s

ii. his average velocity = $\frac{\sqrt{V_{1} ^{2} + V_{2} ^{2} } }{2}$

$V_{1} ^{2}$ = 4 m/s

$V_{2} ^{2}$ = 1.9 m/s

his average velocity = $\frac{\sqrt{4^{2} + 1.9^{2} } }{2}$

= 2.2 m/s

5 0

2 years ago

|3x−2|=19 please help quick thanks

12345 [234]

Answer:

x=7,-17/3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Plsss Helpppp!

vfiekz [6]

Answer:

11/12 = 3/4

Step-by-step explanation:

sorry that's the only one I know :(

5 0

3 years ago

The sum of a number and 6 is 8 more than twice the number. Find the equation that could be used to find this number .

Reil [10]

The correct answer is D

6 0

3 years ago