All categories

3 years ago

63 multiplied by the difference of x and 5. (I would like an explanation too.)

Mathematics

2 answers:

vitfil [10]3 years ago

8 0

63(x-5)
difference= subtraction
do you subtract x by 5, then multiply it by 63

love history [14]3 years ago

6 0

Answer
63 divided by (x-5)

all i can tell you is to re write it as a fraction
63/x-5
if there was an equals sign i would give the answer but since there isn’t i can’t

hope this helps and have a wonderful day :)

You might be interested in

Hi, does anyone know the answer to this question? I’m bad at geometry and I’m struggling to answer it.

vodka [1.7K]

The answer is (2) a translation

Please Mark BRAINLIEST!

3 0

3 years ago

What is the equation of the line whose slope is 1/3 and y-intercept is -4?

faltersainse [42]

Answer:

y=1/3x-4

Step-by-step explanation:

the slope-intercept format of the line is y=mx+b, where m is the slope and b is the y intercept.

we are given the slope (1/3) and the y intercpet (-4).

substitute the numbers into the equation

y=1/3x-4

the answer is y=1/3x-4

hope this helps!

3 0

2 years ago

Estimate the sum of 1.8+4.008+0.44 Round each number to the nearest tenth a.5 b.5.2 c.6 d.6.2

Oduvanchick [21]

Answer:D

Step-by-step explanation:

8 0

3 years ago

Is three quarters of earths water salt water?

aivan3 [116]

The Earth is a watery place. But just how much water exists on, in, and above our planet? About 71 percent of the Earth's surface is water-covered, and the oceans hold about 96.5 percent of all Earth's water. Water also exists in the air as water vapor, in rivers and lakes, in icecaps and glaciers, in the ground as soil moisture and in aquifers, and even in you and your dog.

6 0

3 years ago

Read 2 more answers

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers