All categories

3 years ago

Can you help me solve this?

Mathematics

2 answers:

kvasek [131]3 years ago

7 0

Answer:

y=1/3x+6

Step-by-step explanation:

yulyashka [42]3 years ago

7 0

Answer:

y=1/3x+6

Step-by-step explanation:

You might be interested in

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$

Here

$\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(Z < 2.37 ) - P(Z < -2.37 )$

From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is

$P(Z < 2.37 ) = 0.9911$

and

$P(Z < - 2.37 ) = 0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) =0.9911-0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = 0.9822$

=> $P(| \^ p - p| < 0.05 ) = 0.9822$

3 0

4 years ago

Helppppp!!!!<br> I don’t understand it

oksian1 [2.3K]

Okay so for 2x-y > 3
Subtract -2 from each side
-y>-2x+3
Divide by -1
And when you divid you gotta switch signs
So it’s y<2x-3

3x-5y less than and equal to 25
Subtract 3
-5y is less than and equal to -3x+25
Then divide by -5
Flip since we divide
Y more than and equal to 3/5x-5
We always flip signs when we divid or multiple
I hope this help
Sorry if I’m wrong

6 0

3 years ago

I need help in this question that is in the photo

mihalych1998 [28]

The answer is A, 1. In the statement x^2 >x, if we try 4, 5 and 8 for x, we get 16, 25 and 64 for x^2. The statement is true. But if we try x = 1, when we square it we still have 1. Therefore for x=1, x^2>x is false.

7 0

3 years ago

One

lesantik [10]

$\bf \begin{array}{ccll} oz&calories\\ \cline{1-2} 6&90\\ 64&x \end{array}\implies \cfrac{6}{64}=\cfrac{90}{x}\implies \cfrac{3}{32}=\cfrac{90}{x}\implies 3x=2880 \\\\\\ x=\cfrac{2880}{3}\implies x=960$