The side of a rhombus and the half-diagonals form a right triangle. The length of the other half-diagonal is found from the Pythagorean theorem to be
... d = √((10 cm)² -(6 cm)²) = √(64 cm²) = 8 cm
The length of the other diagonal is 16 cm.
The area is half the product of the diagonal lengths, so is
... area = (1/2)(12 cm)(16 cm) = 96 cm²
3 is incorrect, should be 28.9
16^2 + 18^2 = EG^2
256 + 324
580 = EG^2
EG ≈ 24.08
16^2 + 24.08^2 = AG^2
256 + 580 = AG^2
836 = AG^2
AG ≈ 28.9
5 is incorrect:
The base is 8.
Draw an altitude the base.
Since the triangle is isoceles, it divides the base in half.
Half of that base is 4.
Two right triangles have been formed with one leg 4 and hypotenuse 8.
4^2 + b^2 = 8^2
16 + b^2 = 64
b^2 = 48
b ≈ 6.93
The height of the triangle is 6.93, the base is 8.
A = bh/2 = 8*6.93/2 ≈ 27.7 ≈ 28
2+4=6
6+-7=-1
Your answer would be negative 1 or -1
Answer:
Week=25 Hours
Weekend= 5 Hours
Step-by-step explanation:
So we need to use the info they gave us and create two equations. Firstly we know how much he gets paid per hour during the week (x) and how much he gets paid on the weekend (y).
$20x+$30y=$650
We get this because we know the combined rates he is paid times the hours should add up to the amount he earned.
The next equation will be made off of the information that he worked 5 times as many hours during the week as on the weekend. This tells us that we will take the weekend hours (y) and multiply them by 5 in order to get the week hours (x).
x=5y Now, since we have one variable by itself, we can plug it in for x in the first equation.
20(5y)+30y=650 Our first step here is to distribute the 20 to the 5y in order to eliminate the parenthesis.
100y+30y=650 Next add the like terms together (100y+30y).
Now all we have to do to find y is divide by 130 on both sides to get y alone.
130y=650
________
130 130
y=5 Now to solve for x we just plug our y value into one of the equations above. I'm going to use the second equation.
x=5(5)
x=25
