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Lorico [155]
3 years ago
7

Acetic acid is a polar molecule and can form hydrogen bonds with water molecules. therefore, it has high solubility in water. ye

t acetic acid is also soluble in benzene (c6h6, a nonpolar solvent that lacks the ability to form hydrogen bonds. a solution of 3.8g of ch3cooh in 80g of c6h6 has a freezing point of 3.5 degrees celsius. calculate the molar mass of the solute and suggest what it's structure might be.
Chemistry
1 answer:
Keith_Richards [23]3 years ago
4 0

Colligative properties calculations are used for this type of problem. Calculations are as follows:<span>

</span>Look up the freezing point of benzene, then delta T = f.p.=3.5 = Kf*m 
<span>Solve for molality. </span>

<span>molality = moles/kg solvent </span>
<span>Solve for moles. </span>

<span>moles acetic acid = grams acetic acid/molar mass acetic acid </span>
<span>Solve for molar mass. You would expect to find 60 for the molar mass CH3COOH.</span>

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