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erastovalidia [21]
4 years ago
13

How many grams of O2(g) are needed to completely burn 46.0 g C3H8(g)?

Chemistry
1 answer:
Veronika [31]4 years ago
8 0

Answer:

167,3 grams of O2 (g)

Explanation:

According to the following balanced equation:

C3H8 + 5 02 ---> 3 CO2 + 4 H20

We calculate the mass of the moles:

5 mol O2 = 16grams/mol x2x 5= 160 grams/mol

1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol

If 44 grams C3H8 react with--------- 160 grams O2

46 gramsC3H8 react with    --------X = (46x160)/44 =167, 3 grams O2

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UkoKoshka [18]

Answer:

Molar mass Na2CO3 = 2*23 + 12 + 3*16 = 106 g/ mol

Mass of 1 mol Na2CO3 = 106 g

mass (Na2CO3) = 106g*250cm³/1000cm³ = 26.5 g

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2) Because the solution that was formed after rinsing beaker contains Na2CO3.

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4 years ago
What are the horizontal rows in the periodic table called?
mezya [45]
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3 years ago
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Answer:

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3 years ago
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To solve for moles use molar and volume:

M = mol/L

 

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The proportion of Mercury to HgS is 1:1, as an alternative of doing the obvious math you can conclude that .036 moles of HgS will be produced because you're given .036 moles of Hg and an excess of S. Use the molar mass of HgS to determine how many grams will be produced.

 

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