Answer:
The mass of CO22 in total is 264 g.
The atomic mass for C is 12 g / mole.
The molar mass for CO22 is (12 + (2 × 16)) = 44 g / mole.
m C = (12 / 44) × 264 = 72 g
So, there are 72 g of C in 264 g of CO2
Explanation:
there's the answer have a good day.
When using a dryer to dry your clothes your clothes become synthetic after drying clothes
Answer:
The answer is 12,560
Explanation:
The orbital period is the time a given cosmic question takes to finish one circle around another protest and applies in space science as a rule to planets or space rocks circling the Sun, moons circling planets, exoplanets circling different stars, or double stars. Mercury, for instance, has an orbital time of 88 days while it takes Jupiter around 11.86 years. The time of the Earth's circle is generally thought to be 365 days as timetables appear.
Momentum = (mass) x (velocity) = (1,100) x (30) =
33,000
kg-m/sec due east
Answer:
![1.75272\ \text{m}^3](https://tex.z-dn.net/?f=1.75272%5C%20%5Ctext%7Bm%7D%5E3)
Explanation:
The breakdown reaction of ozone is as follows
![CF_3Cl + UV \rightarrow CF_3 + Cl](https://tex.z-dn.net/?f=CF_3Cl%20%2B%20UV%20%5Crightarrow%20CF_3%20%2B%20Cl)
![Cl + O_3 \rightarrow ClO + O_2](https://tex.z-dn.net/?f=Cl%20%2B%20O_3%20%5Crightarrow%20ClO%20%2B%20O_2)
![O_3 + UV \rightarrow O_2 + O](https://tex.z-dn.net/?f=O_3%20%2B%20UV%20%5Crightarrow%20O_2%20%2B%20O)
![ClO + O \rightarrow Cl + O_2](https://tex.z-dn.net/?f=ClO%20%2B%20O%20%5Crightarrow%20Cl%20%2B%20O_2)
It can be seen that 2 moles of ozone is required in the complete cycle
So for 10 cycles, 20 moles of ozone is required
m = Mass of
= 15.5 g
M = Molar mass of
= 104.46 g/mol
P = Pressure = 24.5 mmHg
T = Temperature = 232 K
R = Gas constant = ![62.363\ \text{L mmHg/K mol}](https://tex.z-dn.net/?f=62.363%5C%20%5Ctext%7BL%20mmHg%2FK%20mol%7D)
Number of moles is given by
![n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{15.5}{104.46}\\\Rightarrow n=0.1484\ \text{moles}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7Bm%7D%7BM%7D%5C%5C%5CRightarrow%20n%3D%5Cdfrac%7B15.5%7D%7B104.46%7D%5C%5C%5CRightarrow%20n%3D0.1484%5C%20%5Ctext%7Bmoles%7D)
![20\ \text{moles} = 20\times 0.1484 = 2.968\ \text{moles}](https://tex.z-dn.net/?f=20%5C%20%5Ctext%7Bmoles%7D%20%3D%2020%5Ctimes%200.1484%20%3D%202.968%5C%20%5Ctext%7Bmoles%7D)
From ideal gas law we have
![PV=nRT\\\Rightarrow V=\dfrac{nRT}{P}\\\Rightarrow V=\dfrac{2.968\times 62.363\times 232}{24.5}\\\Rightarrow V=1752.72\ \text{L}=1.75272\ \text{m}^3](https://tex.z-dn.net/?f=PV%3DnRT%5C%5C%5CRightarrow%20V%3D%5Cdfrac%7BnRT%7D%7BP%7D%5C%5C%5CRightarrow%20V%3D%5Cdfrac%7B2.968%5Ctimes%2062.363%5Ctimes%20232%7D%7B24.5%7D%5C%5C%5CRightarrow%20V%3D1752.72%5C%20%5Ctext%7BL%7D%3D1.75272%5C%20%5Ctext%7Bm%7D%5E3)
For 20 cycles of the reaction the volume of the ozone is
.