Solution:-
- a=Carbon(c)
- b=Nitrogen ion(N+)
- c=Oxygen ion(O-)
Now
#1
Let's look at the EC of carbon(Z=6)

Now.
3 electrons are shared(1 with H_3C and 2 with N+)
Hence
Electron left unshared=4-3=1
#2
Lets look at EC of Nitrogen(N),Z=7

- Valency is 3
- It has already shared 3 electrons
But
Its Cation i.e N+
- Hence 1 electron it donated .Now it has valency 4
Hence
Electron left unshared=4-3=1
#3
Lets look at EC of Oxygen(Z=8)

But it is anion hence 1electron required more which us bonded
Hence
Number of electrons left unshared=0
Im not certain but i believe it is the Magnitude
Answer:
34.8 moles of O
Explanation:
First we break down Al2(SO4)3 and look at SO4 only. In this compound, there are already 4 moles of O. Then you see that there are 3 moles of (SO4), meaning there are 3*4 moles of O = 12 moles in the entire compound. Then you look at the question, where it's asking for 2.9 moles of the entire Al2(SO4)3 compound, so you multiply 2.9*12 = 34.8 total moles of O.
A chemical reaction must occur for a compound to have different properties.