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2 years ago

Question and answers in imageeeeee

Mathematics

2 answers:

FromTheMoon [43]2 years ago

4 0

Answer:

red goes with diameter

vfiekz [6]2 years ago

3 0

Answer:

red= circumfrence

black= diameter

green= radius

yellow= area

Step-by-step explanation:

You might be interested in

Management at a seaside resort is publishing a brochure and wants to include a statement about the proportion of clear days duri

Ymorist [56]

Answer: B. 264

Step-by-step explanation:

Formula to calculate the sample size 'n' , if the prior estimate of the population proportion (p) is available:

$n= p(1-p)(\dfrac{z}{E})^2$

, where z = Critical z-value corresponds to the given confidence interval

E= margin of error

Let p be the population proportion of clear days.

As per given , we have

Prior sample size : n= 150

Number of clear days in that sample = 117

Prior estimate of the population proportion of clear days = $p=\dfrac{117}{150}$

E= 0.05

The critical z-value corresponding to 95% confidence interval = z*= 1.95 (By z-table)

Then, the required sample size will be :

$n= \dfrac{117}{150}(1-\dfrac{117}{150})(\dfrac{1.96}{0.05})^2$

Simplify ,

$n= (0.1716)(39.2)^2$

$n= 263.687424\approx264$

Hence, the sample size necessary to construct this interval =264

Thus the correct option is B. 264

7 0

3 years ago

Please help!!!!!!!<br> picture below

xxMikexx [17]

Answer:

the first equation could be something along the lines of $y=3x^{2}$ then the second is $y=3x^{2} -3\\$

Step-by-step explanation:

this is how shifting works

6 0

1 year ago

The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th

12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = $\dfrac{2400 \ cm^2}{p}$

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be $\dfrac{2400 \ cm^2}{p} + 20$

The area of the printed material can now be: $A = (p+30)(\dfrac{2400 }{p} + 20)$

= $2400 +20 p +\dfrac{72000}{p}+600$

Let differentiate with respect to p; we have

$\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}$

Also;

$\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}$

For the smallest area $\dfrac{dA}{dp }=0$

$20 - \dfrac{72000}{p^2}=0$

$p^2 = \dfrac{72000}{20}$

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression q = $\dfrac{2400 \ cm^2}{p}$ to solve for q;

q = $\dfrac{2400 \ cm^2}{p}$

q = $\dfrac{2400 \ cm^2}{60}$

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = $\dfrac{2400 \ cm^2}{p} + 20$ = $\dfrac{2400 \ cm^2}{60} + 20$ = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

4 0

3 years ago

What is the value of x? Enter your answer, as a decimal, in the box.

nlexa [21]

Whats the problem for this?

5 0

3 years ago

Plz help with 6,7,8 and 9

Reil [10]

Grayson's mistake was that he multiplied 4 and 3 and then used the exponent he had to square 3 and then multiply it by 4.

Emily's mistake was that she added 2 to 36 instead of multiplying it by -2

Pat's mistake was that he forget to make y into -2 instead of 2

The right way to do this is 4(3^2)+2(-2)
(3^2)=9 9×4=36 2(-2)=-4 -4+9=5

3 0

3 years ago