Use the depreciation formula.
Where 'p' is the principal value, 'r' is the rate it depreciates, and 'n' is the time. Just plug in what we know:
Simplify by subtracting:
Simplify the exponent:
Multiply:
Answer:
iii. priceof a house in Saratoga, N.Y.
Step-by-step explanation:
In this question, we take a sample from house prices of 1728 houses in Saratoga, New York.
Since only houses from Saratoga are part of the sample, the response variable will be related only to Saratoga.
In this question:
Sample to find house prices in Saratoga, which is the variable of interest. The correct answer is given by option iii.
Answer:
Step-by-step explanation:
E) y +17 =2
y =2-17 = -15
A) 19=a+5
a=19-5= 14
Y) n-6= -50
n=-50+6= -44
L) let the number be p
p+9= -30
p = -30-9= -39
L) -9 + m =20
m = 20+9 = 29
E) 7 = x -23
x = 7+23 = 30
W) 8 +q = -11
q = -11-8 = -19
T) k -8 = -3
k = -3+8 = 5
T) 3 = 10+v
v = 3-10 = -7
H) t-(-1) =45
t+1 =45
t = 45-1 = 44
N) let the number be b
b-20 = -75
b = -75+ 20 = -55
Q) x + (-3) = 22
x = 22+3 = 25
E) p-(-3) =100
p+3=100
p = 100-3 =97
T) 25 + d =8
d = 8-25 = -17
C) -16 + b = 32
b = 32+16 = 48
L) w+38=5
w = 5-38 = -33
O) j+(-61)= -2
j = -2+61 = 59
H) -9 = h+47
h = -9-47 = -56
E) 13=x-13
x = 13+13 = 26
O) t-(-29) = 29
t+29 = 29
t = 29-29 = 0
If you simplify 12 over 6, you get 2 pounds for $1. And it is 50 cents for one pound, so you need to find it for 3 pounds. It would be $1.50
