Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
Quickly using a calculator (or long division) reveals that 191/238=<span>0.8025=80.25%, which is close to 80%=4/5
Similarly, 106/160=0.6625=66.25%, which is close to 66.67%=2/3</span>
17 because 4 x 1.5 = 6, 50 / 1.5 = 33.33
Answer:
D.) 8:00
It’s a geometric problem so when plugged in you get answer D
Given:
Four equations in the options.
To find:
The equation which represents a proportional relationship.
Solution:
If y is proportional to x, then
where, k is the constant of proportionality.
In this case if x=0, then y=0. It means the graph of a proportional relationship passes through the origin.
From the given options, only option B, i.e., 
, is of the , where, 
.
So, the equation represents a proportional relationship.
Therefore, the correct option is B.
