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aleksklad [387]
3 years ago
6

Please help with is im so confused!​

Mathematics
1 answer:
Kamila [148]3 years ago
7 0
The answer should be A:) hoped this helped
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Will give brainiest, need help
eimsori [14]

Answer:

f(6) = 53

Step-by-step explanation:

f(x) = 10x - 7

We want to find f(6)

To do so simply substitute 6 for x in the equation

Equation: 10x - 7

x = 6

f(6) = 10(6) - 7

multiply 10 and 6

f(6) = 60 - 7

subtract

f(6) = 53

8 0
3 years ago
Read 2 more answers
Please asap!!!!! (photo below)
Bond [772]

Answer:

132 degrees

Step-by-step explanation:

these angles are Alternate interior angles so angle A is congruent to angle B.

5x-18 = 3x+42

-3x         -3x

2x-18 = 42

+18       +18

2x    =   60

÷2     ÷2

x=30

A=5(30) -18

  = 150-18

  = 132 degrees

HOPE THIS HELPS

6 0
4 years ago
Whats 1/5 + -4 having trouble
garri49 [273]
1/5+ (-4) is the same as 1/5 - 4
1/5-20/5
-19/5
4 0
3 years ago
Read 2 more answers
PLS HELP!! WILL MAKE BRAINLIEST!!!!
poizon [28]

Answer:

(86.2,0) is the x-intercept.

Step-by-step explanation:

You can use the slope formula to figure this one out:

Just use two of the points on the table, any of them will work:

(33,-22)\\(52,-33)

\frac{-22-33}{33-52} =\frac{-55}{-19}=\frac{55}{19}

Now you have the slope of the equation, now using the y-intercept equation you can substitute the variables for point of the table and the new slope.:

(71,-44)\\y=mx+b\\-44=\frac{55}{19} (71)+b

Now just solve for b to get the y intercept:

-44=\frac{55}{19}(71)+b\\-44= \frac{3905}{19} +b\\(-\frac{3905}{19})-44=\frac{3905}{19} +b(-\frac{3905}{19})\\   -\frac{4741}{19}=b

Now you have the y-intercept so you just have to plug in 0 to the y spot and it will calculate the x-intercept.

0=\frac{55}{19}x-\frac{4741}{19}\\(+\frac{4741}{19})0=\frac{55}{19}x-\frac{4741}{19}(+\frac{4741}{19})\\\\\frac{4741}{19}=\frac{55}{19}x\\\frac{\frac{4741}{19}}{\frac{55}{19} }= \frac{\frac{55}{19} x}{\frac{55}{19} } \\\frac{431}{5} =x\\or\\86.2=x

And that's the x-intercept.

5 0
2 years ago
Read 2 more answers
If f(x)=x squared-2x and g(x) = 6x+4 for which is a value of x does (f+g)(x) =0
ra1l [238]

Answer:

For x = -2

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question:

f(x) = x^2 - 2x

g(x) = 6x + 4

f(x) + g(x) = (f+g)(x)  = x^2 - 2x + 6x + 4 = x^2 + 4x + 4

Which is a value of x does (f+g)(x) =0

x^2 + 4x + 4

Quadratic equation with a = 1, b = 4, c = 4

So

\Delta = 4^{2} - 4*1*4 = 0

x_{1} = \frac{-4 + \sqrt{0}}{2} = -2

x_{2} = \frac{-4 - \sqrt{0}}{2} = -2

For x = -2

7 0
3 years ago
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