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Juli2301 [7.4K]
3 years ago
11

Please help me with this I will give brainliest please answer it right

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

A

Step-by-step explanation:

RR, RY, RG, RP, YY, YG, YP, YR, GG,GP, GR, PP, PR, PY, PG.

All combinations of the four colors are provided in Option A as written out above. The other options are missing combinations.

I hope I helped, Would appreciate Brainliest! ;)

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V + 9<br> ---------- = 8 <br> 3<br><br> Can someone help me ??
bagirrra123 [75]
\frac{v + 9}{3} = 8

Multiply both sides by 3, because 3 is our denominator (bottom number in a fraction), and we want to get rid of the denominator.

3 × (v + 9) = 8 × 3

Simplify.

3v + 27 = 24

Then, subtract both sides by 27.

3v = 24 - 27

Simplify.

3v = -3

Divide both sides by 3.

v = -1

~Hope I helped!~
4 0
3 years ago
Simplify the expression
SashulF [63]

Answer:

1/(c - d)

Step-by-step explanation:

Multiply numerator and denominator by cd, then factor the denominator and cancel the common factor. (The result is restricted to c+d ≠ 0.)

\displaystyle\frac{\frac{1}{c}+\frac{1}{d}}{\frac{c}{d}-\frac{d}{c}}=\frac{d+c}{c^2-d^2}\\\\=\frac{d+c}{(c-d)(d+c)}=\frac{1}{c-d}

4 0
3 years ago
Read 2 more answers
One side of a rectangle is 10 feet shorter than twice another side. Find the length of the shorter side if we also know the peri
seropon [69]

Answer:

  6 feet

Step-by-step explanation:

Let x represent the length of "another side." Then "one side" is ...

  2x -10 . . . . . . 10 feet shorter than twice another side

The sum of these two side lengths is half the perimeter, so is ...

  x + (2x -10) = 14 . . . . . two sides are half the perimeter

  3x = 24 . . . . . . . . . . . . add 10, collect terms

  x = 8 . . . . . . . . . . . . . . .divide by the coefficient of x

  (2x -10) = 2·8 -10 = 6 . . . . find "one side"

We have found "one side" to be 6 feet long, and "another side" to be 8 feet long. The shorter side is 6 feet.

8 0
3 years ago
I don't understand :/
makkiz [27]

Answer:

The frequency is relatable

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Find the complex zeros of x^3+27. write f in factored form
aliina [53]
x^3+27=0&#10;\\x^3+3^3=0&#10;\\(x+3)(x^2-3x+9)=0&#10;\\x^2-3x+9=0&#10;\\a=1,b=-3,c=9&#10;\\&#10;\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} &#10;\\&#10;\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0&#10;&#10;
4 0
3 years ago
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