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3 years ago

I need help on thisss —> 8x4=8(2+_)

Mathematics

1 answer:

abruzzese [7]3 years ago

3 0

Answer: 2

Step-by-step explanation:

8x4=32, you have to distribute the 8 into the parentheses so you will have 8x2+8x2 which is 16+16=32

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(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

2 years ago

I need the answers to these if you can’t read it it says “You drink 16 Fluid ounces of milk for breakfast every morning”.

Reika [66]

Answer: A. y = 16 x

B. 8 days

Step-by-step explanation:

A) Here, 16 Fluid ounces of milk is used for breakfast every morning.

In one day the consumption of milk = 16 fluid ounces

In x days the consumption of milk = 16 x fluid ounces

Thus, if y be the total milk in ounces that is used in x days,

The required function,

y = 16 x

B) In 1 day, consumption of milk = 16 ounces

⇒ $16\text{ ounces milk } = 1 \text{ day}$

⇒ $8\times 16\text{ ounces milk } = 8\times 1 \text{ day}$

⇒ $128\text{ ounces milk } = 8 \text{ day}$

Since, 128 ounces = 1 gallon

⇒ $1\text{ gallon milk } = 8 \text{ day}$

In 8 days, 1 gallon of milk will consumed.

4 0

3 years ago

Help asappppp!!!!!!right now !

noname [10]

Answer:

Step-by-step explanation:

tanx=17/100

so do the inverse so it would be tan^-1 (17/100)= degrees

3 0

3 years ago

Read 2 more answers

For the school play, tickets cost $9.50 for adults and $3 for kids under 12. What would be the total cost for 8 adult tickets an

saul85 [17]

Answer:

$139
9.5aa +3kk

Step-by-step explanation:

8 adult tickets cost 8($9.50) = $76

21 kids tickets cost 21($3) = $63

The total cost of these tickets is $76 +63 = $139.

aa adult tickets cost 9.50aa

kk kids tickets cost 3.00kk

The total cost of these tickets is 9.50aa +3.00kk.

_____

<em>Additional comment</em>

We ordinarily expect a variable to be a single letter. This problem statement defines each variable using a double letter, so that is what we have used. (Sometimes Brainly doubles up variable content in copied text, so we suspect that may have happened here.)

4 0

2 years ago

Someone please help with this problem

den301095 [7]

A) write an equation you can solve to find the cost of one ticket
x=cost of one ticket.
9x+5=104

b)
I have to solve this equation.
1)adding -5 to each side
2) dividing both sides by 9

c)
9x+5=104
1) 9x+5-5=104-5
9x=99
2) 9x/9=99/9
x=11

the cost of each ticket was $11

3 0

2 years ago