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Alexandra [31]
3 years ago
6

2C4H10+13O2-->8CO2+10H2O Using the predicted and balanced equation, How many Liters of CO2 can be produced from 150 grams of

C4H10?
Chemistry
1 answer:
Anna11 [10]3 years ago
8 0

Answer:  233 L of CO_2 will be produced from 150 grams of  C_4H_{10}

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of} C_4H_{10}=\frac{150g}{58g/mol}=2.59moles

The balanced chemical equation is:

2C_4H_{10}+13O_2(g)\rightarrow 8CO_2+10H_2O  

According to stoichiometry :

2 moles of C_4H_{10} produce =  8 moles of CO_2

Thus 2.59 moles of C_4H_{10} will produce=\frac{8}{2}\times 2.59=10.4moles  of CO_2  

Volume of CO_2=moles\times {\text {Molar volume}}=10.4moles\times 22.4mol/L=233L

Thus 233 L of CO_2 will be produced from 150 grams of  C_4H_{10}

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If 63.8 grams of aluminum metal (Al) react with 72.3 grams of sulfur (S) in a synthesis reaction, how many grams of the excess r
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23.2 g of Al will be left over when the reaction is complete

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As I have 2.25 mole of S, and I need 3.54 S, is my limiting reagent so the limiting in excess is the Al.

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