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Sveta_85 [38]
3 years ago
15

What's 2+7 hehdhenbeidbnejdbdbdbdi

Chemistry
1 answer:
Feliz [49]3 years ago
4 0

Answer:

Answer

9......

Explanation:

Explaination:

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Help. due today. thx :)
vekshin1
I believe the correct answer is D
3 0
4 years ago
how many hydrogen moles are in 11.19 grams of hydrogen? Also how many oxygen moles are in 88.8 grams of oxygen?
yarga [219]
The hydrogen moles and the oxygen between each other are that the oxygen had 88.8 grams and hydrogen has 11.19
6 0
3 years ago
If you were in Canada and purchased a 1 kg apple at the grocery,how many grams were in the apple?
Triss [41]

Answer:

1000 gram

Explanation:

because mass is constant everywhere

4 0
3 years ago
Determine the mass of 5.2 x 10 power of 21 molecules of propanol C3H7OH(l), on grams.
Alja [10]

n(\text{C}_3\text{H}_7\text{OH}) = N(\text{C}_3\text{H}_7\text{OH}) / N_A\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 5.2 \times 10^{21} / (6.02 \times 10^{23})\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 8.6 \times 10^{-3} \; \text{mol}

where N_A = 6.02 \times 10^{23}\; \text{mol}^{-1} the Avogadro's constant that relates the number of particles to their number, in the unit moles \text{mol}.

The molar mass of propanol- mass per mole propanol- can be directly deduced from its molecular formula with reference to a modern periodic table.

M(\text{C}_3\text{H}_7\text{OH}) = \underbrace{3 \times 12.01}_{\text{carbon}} + \underbrace{8 \times 1.008}_{\text{hydrogen}} + \underbrace{1\times 16.00}_{\text{oxygen}} = 60.09 \; \text{g} \cdot \text{mol}^{-1}

8.6 \times 10^{-3} \; \text{mol} of propanol molecules would thus have a mass of 8.6 \times 10^{-3} \; \text{mol} \times 60.09 \; \text{g} \cdot \text{mol}^{-1} = 0.52 \; \text{g}

5 0
4 years ago
If carbon-15 has a half-life of 2.5 seconds, % of the sample would still be
kramer

Answer:

After 5 second 25% C-15 will remain.

Explanation:

Given data:

Half life of C-15 = 2.5 sec

Original amount = 100%

Sample remain after 5 sec = ?

Solution:

Number of half lives = T elapsed / half life

Number of half lives = 5 sec / 2.5 sec

Number of half lives = 2

At time zero = 100%

At first half life = 100%/2 = 50%

At second half life = 50%/2 = 25%

Thus after 5 second 25% C-15 will remain.

8 0
4 years ago
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