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choli [55]
3 years ago
6

Which of the following is a way that some animals bodies adapt to living in extremely cold climates

Chemistry
2 answers:
HACTEHA [7]3 years ago
7 0
B hibernation but it deppends on the animal
ratelena [41]3 years ago
6 0

Answer : The correct answer is B ) Hibernation .

Adaptation is a process where an animal well suited in surrounding area with time . Animals living in extremely cold habitat adapts their body which can protect them against cold . If the options are checked :

A) Clusters : Clusters is adaptation done by marine animals . They form clusters which are called as " Beds " on surfaces which provide shelter to many plants .

B) Hibernation : It is state of inactivity or winter dormancy . This is extended sleep by animals by reducing their metabolic rates and lowering of body temperature in scarcity of food in extreme cold winters. SO we can Hibernation is adapted by cold animals to survive from extreme cold.

C) Burrows : Burrows are tunnels dug by animals basically by desert animals to protect themselves from scorching heat or by animals for protection .

D) Estivation : This is similar to hibernation , state of dormancy but in very hot and dry season . Animals during summer ( hot and dry ) go to underground where the environment is cooler to protect themselves from excessive loss of water . So it is adaptation of desert animals ,

Hence Hibernation is correct adaptation for cold animals .

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Identify the main purpose of the Periodic Table. *
saw5 [17]

The periodic table is one of the most important tools in the history of chemistry. It describes the atomic properties of every known chemical element in a concise format, including the atomic number, atomic mass and relationships between the elements. Elements with similar chemical properties are arranged in columns in the periodic table.

The table thus is a quick reference as to what elements may behave the same chemically or which may have similar weights or atomic structures.

Hope this answer helps you

4 0
3 years ago
A piece of an unknown substance weighing 124.0 grams is heated in boiling water to 100.0oc. when the substance is placed in a ca
MakcuM [25]

The heat cause 300g water temperature increase from 20 to 26 celcius. The heat transferred would be: 300g * (26 °C -20 °C) *4.2 joule/gram °C= 7560J

The unknown substance is added to the water, so its final temperature should be the same as the water. The calculation would be:

7560J= 124g * (100-26)* specific heat

specific heat= 7560J / 124g / 74 °C= 0.8238 J/gram °C

3 0
3 years ago
How many half-lives would something have gone through if you had 75% daughter product and 25% parent?
levacccp [35]

Answer:

Two Half-lives

Explanation:

Let number of Parent nuclei Initially present be X,

Then, finally \frac{X}{4} Parent nuclei Will remain with \frac{3X}{4} daughter nuclei.

In one half- life , parent nuclei becomes half of initial.

So, starting with X parent nuclei,

After one half-life, it will degrade to \frac{X}{2} .

After another half life , Parent nuclei will become half of \frac{X}{2}

Which is equal to \frac{X}{4}.

So, Parent nuclei have to go through Two half-lives.

6 0
3 years ago
The density of pure solid copper is 8.94 g/mL. What volume does 34 g of copper occupy?
patriot [66]

hey there ! :

Density = 8.94 g/mL

mass = 34 g

Volume = ??

Therefore:

D = m / V

8.94 = 34 / V

V = 34 / 8.94

V = 3.803 mL

Hope this helps!

4 0
3 years ago
Which statement is true about a polyatomic ion?
andrew11 [14]

Answer:

The correct answer is that it is made of atoms that are covalently bonded together.

Explanation:

Hope this helped Mark BRAINLEST!!!

5 0
2 years ago
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