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choli [55]
3 years ago
6

Which of the following is a way that some animals bodies adapt to living in extremely cold climates

Chemistry
2 answers:
HACTEHA [7]3 years ago
7 0
B hibernation but it deppends on the animal
ratelena [41]3 years ago
6 0

Answer : The correct answer is B ) Hibernation .

Adaptation is a process where an animal well suited in surrounding area with time . Animals living in extremely cold habitat adapts their body which can protect them against cold . If the options are checked :

A) Clusters : Clusters is adaptation done by marine animals . They form clusters which are called as " Beds " on surfaces which provide shelter to many plants .

B) Hibernation : It is state of inactivity or winter dormancy . This is extended sleep by animals by reducing their metabolic rates and lowering of body temperature in scarcity of food in extreme cold winters. SO we can Hibernation is adapted by cold animals to survive from extreme cold.

C) Burrows : Burrows are tunnels dug by animals basically by desert animals to protect themselves from scorching heat or by animals for protection .

D) Estivation : This is similar to hibernation , state of dormancy but in very hot and dry season . Animals during summer ( hot and dry ) go to underground where the environment is cooler to protect themselves from excessive loss of water . So it is adaptation of desert animals ,

Hence Hibernation is correct adaptation for cold animals .

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How much 5.50M NaOH must be added to 680.0 mL of a buffer that is 0.0215 M acetic acid and 0.0270 M sodium acetate to raise the
Lelu [443]

5.50M NaOH must be added to 680.0 mL of a buffer, The amount of NaOH  is mathematically given as

V=2.107mL

<h3>What is the volume of 5.50M NaOH?</h3>

Generally, the equation for Chemical Reaction is mathematically given as

CH3COOH+OH^{-} ⇄ CHCOO^{-} + H2O

Therefore

pka=-log(1.8*10{-5})

pKa=5-0.25527

pKa=4.3447

Hence

pH=pKa+log\frac{CH3COO}{CH3COOH}\\\\0.75=4.7447+log\frac{0.01564+x}{0.01428-x}

x=0.0115898

Volume of NaOH

V=0.0021072L

V=2.107mL

Read more about Chemical Reaction

brainly.com/question/11231920

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5 0
2 years ago
Gas expands as it heats up. We call this phenomena...
ra1l [238]

I believe the answer is thermal expansion.

7 0
3 years ago
Read 2 more answers
Determine the mass of 5.2 x 10 power of 21 molecules of propanol C3H7OH(l), on grams.
Alja [10]

n(\text{C}_3\text{H}_7\text{OH}) = N(\text{C}_3\text{H}_7\text{OH}) / N_A\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 5.2 \times 10^{21} / (6.02 \times 10^{23})\\ \phantom{n(\text{C}_3\text{H}_7\text{OH})} = 8.6 \times 10^{-3} \; \text{mol}

where N_A = 6.02 \times 10^{23}\; \text{mol}^{-1} the Avogadro's constant that relates the number of particles to their number, in the unit moles \text{mol}.

The molar mass of propanol- mass per mole propanol- can be directly deduced from its molecular formula with reference to a modern periodic table.

M(\text{C}_3\text{H}_7\text{OH}) = \underbrace{3 \times 12.01}_{\text{carbon}} + \underbrace{8 \times 1.008}_{\text{hydrogen}} + \underbrace{1\times 16.00}_{\text{oxygen}} = 60.09 \; \text{g} \cdot \text{mol}^{-1}

8.6 \times 10^{-3} \; \text{mol} of propanol molecules would thus have a mass of 8.6 \times 10^{-3} \; \text{mol} \times 60.09 \; \text{g} \cdot \text{mol}^{-1} = 0.52 \; \text{g}

5 0
4 years ago
If the cell could no longer produce ATP, what would be the effect on the sarcoplasmic reticulum? If the cell could no longer pro
navik [9.2K]

Answer:

A. The muscle would not contract.

Explanation:

The sarcoplasmic reticulum is a specialized smooth endoplasmic reticulum that transmits electrical impulses and is the primary regulator of calcium storage, release, and reuptake. On the other hand, glycolysis and the mitochondria are responsible for cellular ATP production.

In the muscle, the SR and mitochondrial function are interconnected, ATP is used to lower myoplasmic calcium levels during muscle relaxation, this means that muscle contractility is linked to the control of sarcomeric Ca2+ delivery/removal and ATP generation/utilization.<em> If we have a failure to remove Ca2+ from the cytosol by not producing ATP, the muscle will be prevented from relaxation, subsequently there will be a decrease in muscle contraction too.</em>

I hope you find this information useful and interesting! Good luck!

7 0
3 years ago
A good way to organize and record your results and observations is
Zielflug [23.3K]
It is a graph. It shows observations and then you record your results with any of the graph types.
5 0
3 years ago
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