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choli [55]
3 years ago
6

Which of the following is a way that some animals bodies adapt to living in extremely cold climates

Chemistry
2 answers:
HACTEHA [7]3 years ago
7 0
B hibernation but it deppends on the animal
ratelena [41]3 years ago
6 0

Answer : The correct answer is B ) Hibernation .

Adaptation is a process where an animal well suited in surrounding area with time . Animals living in extremely cold habitat adapts their body which can protect them against cold . If the options are checked :

A) Clusters : Clusters is adaptation done by marine animals . They form clusters which are called as " Beds " on surfaces which provide shelter to many plants .

B) Hibernation : It is state of inactivity or winter dormancy . This is extended sleep by animals by reducing their metabolic rates and lowering of body temperature in scarcity of food in extreme cold winters. SO we can Hibernation is adapted by cold animals to survive from extreme cold.

C) Burrows : Burrows are tunnels dug by animals basically by desert animals to protect themselves from scorching heat or by animals for protection .

D) Estivation : This is similar to hibernation , state of dormancy but in very hot and dry season . Animals during summer ( hot and dry ) go to underground where the environment is cooler to protect themselves from excessive loss of water . So it is adaptation of desert animals ,

Hence Hibernation is correct adaptation for cold animals .

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use a mortar & pestle to grind the solute into smaller particles, thus increasing the surface area.


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Answer: The movement of heat from a warmer object to a cooler one is called heat transfer

Explanation:

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3 years ago
g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empir
sammy [17]

Answer:

THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O

Explanation:

The empirical formula for the unknown compound can be obtained by following the processes below:

1 . Write out the percentage composition of the individual elements in the compound

C = 75.68 %

H = 8.80 %

O = 15.52 %

2. Divide the percentage composition by the atomic masses of the elements

C = 75 .68 / 12 = 6.3066

H = 8.80 / 1 = 8.8000

O = 15.52 / 16 = 0.9700

3. Divide the individual results by the lowest values

C = 6.3066 / 0.9700 = 6.5016

H = 8.8000 / 0.9700 = 9.0722

O = 0.9700 / 0.9700 = 1

4. Round up the values to the whole number

C = 7

H = 9

O = 1

5 Write out the empirical formula for the compound

C7H90

In conclusion, the empirical formula for the unknown compound is therefore C7H9O

7 0
3 years ago
Sodium (Na) is an explosive metal, while Chlorine (CI) is a toxic gas. However, when bonded together they form regular table sal
RUDIKE [14]

Answer:

When a sodium atom transfers an electron to a chlorine atom, forming a sodium cation (Na+) and a chloride anion (Cl-), both ions have complete valence shells, and are energetically more stable. The reaction is extremely exothermic, producing a bright yellow light and a great deal of heat energy.

5 0
2 years ago
Classify each of these compounds as a Brønsted-Lowry acid, a Brønsted-Lowry base, or neither.
chubhunter [2.5K]

Answer:

Brønsted-Lowry acid : H2SO4, HF, HNO2

Brønsted-Lowry Base : NH3, C3H7NH2, CH3)3N

Neither : NaBr, CCl4

Explanation:

8 0
3 years ago
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