6 times 8…………zzzzzzzzzzzzzzzzz
Answer: 
Step-by-step explanation:
First, it is needed to determined the values for x = 1 and x = 2:

The sign change within the interval is the most sound evidence of the root existence. According to the Intermediate Value Theorem, there is a number
such that
. Another finding is that
is closer to 1 than to 2.
![c = a + \frac{b-a}{f(b)-f(a)}\cdot[f(c)-f(a)]](https://tex.z-dn.net/?f=c%20%3D%20a%20%2B%20%5Cfrac%7Bb-a%7D%7Bf%28b%29-f%28a%29%7D%5Ccdot%5Bf%28c%29-f%28a%29%5D)
![c = 1 + \frac{2-1}{4-(-1)}\cdot[0-(-1)] \\c = 1.2](https://tex.z-dn.net/?f=c%20%3D%201%20%2B%20%5Cfrac%7B2-1%7D%7B4-%28-1%29%7D%5Ccdot%5B0-%28-1%29%5D%20%5C%5Cc%20%3D%201.2)
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❖ x = 32
x:50
16:25
The pattern here is divide by 2 (or if doing the opposite way, multiply by 2.)
16 x 2 = 32, so x = 32
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2m-4 = x+nx switch sides
2m-4 = x (1+n) common factor
2m-4/1+4 = x divide both side by 1-x