Tan t= 8/15
cot t= 15/8
csc t=-17/8
use sohcahtoa and the reciprocals
Answer:
5
Step-by-step explanation:
1) Solve for the slope(m):
(y2-y1) / (x2-x1)
pick any
(-3 - (-5) )/ (1 - 0)
(-3 + 5) / (1 - 0)
2/1 = 2
2) b(intercept) value is found when x = 0:
x = 0, y = -5,
b = y
b = -5
3) Plug it in:
y = mx + b
y = 2x - 5
4) when the value is 5, x = 5:
y = 2x - 5
y = 2(5) - 5
y = 10 -5 = 5
Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
Take the coefficient of the x-term, half it, then square that. add this to both sides
x² + 16x. coefficient of x is 16. half of 16 is 8. 8²=64
x² + 16x + 64 =64. this is your answer but to continue
x² + 16x + 64 = 64
(x+8)² = 64
x+8 = ✓64
x+ 8 = ±8
x = 0 or -16
