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forsale [732]
3 years ago
6

Hey stob it. Please help me. Cmon help me. Plz.

Physics
1 answer:
Anna [14]3 years ago
6 0

Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

v_y = 31 × 0.8660

v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

v ≈ 31 m/s

4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

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Bella makes the 6.1m distance to her food bowl in 8.8 seconds what is her average velocity
storchak [24]
Bella’s average velocity is about 0.693 meters per second.

To find the average velocity, you must divide the distance by the change in time, which should look like v=d/t

Here is how you set up the equation-
v=6.1/8.8

Once you divide 6.1 meters by 8.8 seconds, you should get a number that looks like 0.69318182.... however, I just rounded it to 0.693 meters per second. You can round it to whatever you like.

Hope this helped! If you have any questions about what I mentioned in my answer or explanation, feel free to comment on my answer and I’ll try to get back to you!
8 0
3 years ago
What is the magnitude of the kinetic frictional force
Effectus [21]

The magnitude of the kinetic friction force, ƒk, on an object is. Where μk is called the kinetic friction coefficient and |FN| is the magnitude of the normal force of the surface on the sliding object. The kinetic friction coefficient is entirely determined by the materials of the sliding surfaces. hope it helps

4 0
3 years ago
A 1.0-kg block of aluminum is at a temperature of 50 Celsius. How much thermal energy will it lose when it’s temperature is redu
Ipatiy [6.2K]

Answer:

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Explanation:

Given data,

The mass of aluminium block, m = 1.0 kg

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The final temperature of the block, T' = 25° C

The change in temperature, ΔT = 50° C - 25° C

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The specific heat capacity of aluminium, c = 900  J/kg°C

The formula for thermal energy,

                             <em>Q = mcΔT</em>

                                 = 1.0 x 900 x 25

                                 = 22500 J

Hence, the lose of thermal energy is, Q = 22500 J

7 0
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Hatshy [7]
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Hope this helps!
6 0
3 years ago
I need help with this someone help me?
Brilliant_brown [7]
Graph A so answer B also why isn’t answer a with graph A and B with graph B etc like that’s just confusing lol
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