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forsale [732]
2 years ago
6

Hey stob it. Please help me. Cmon help me. Plz.

Physics
1 answer:
Anna [14]2 years ago
6 0

Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

v_y = 31 × 0.8660

v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

v ≈ 31 m/s

4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

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You have a set of calipers that can measure thicknesses of a few inches with an uncertainty of 0:005 inches. I mesure the thickn
solmaris [256]

To solve this problem we will apply the concepts related to the calculation of significant figures under tolerance levels. We will also take into account that the number of significant digits at the end of an answer must not be greater than the number of significant digits of a number:

PART A) The thickness of the 52 cards is

T = 0.590 \pm 0.005 in

The thickness, t, of 1 card can be:

t = \frac{0.590}{52} \pm \frac{0.005}{52} in

t = 0.0113461\pm 0.000096 in

The thickness of 52 cards has 3 significant figures and the uncertainty has 1 significant digit. So

the significant figures of the thickness of one card and the uncertainty should also be 3 and 1 respectively

t = 0.01134 \pm 0.005 in

t = 0.0113 \pm 0.0001 in

Therefore the thickness of one card is \mathbf {t = 0.0113 \pm 0.0001 in }

PART B) One card has uncertainty of 0.0001 in if measured using 1 deck.

The number of decks, n, required to create the uncertainty of 0.00002 in is

n = \frac{0.0001}{0.00002}

n = 5

Therefore, 5 decks are required to measure the thickness of one card with an uncertainty of 0.00002 in

6 0
3 years ago
Examples of how thermal energy transfer by conduction, convection, or radiation.
____ [38]
Microwave Radiation. Microwave radiation utilizes short, high-frequency waves that penetrate food, which agitates its water molecules to create friction and transfer heat. If you're heating a solid substance, this heat energy is transferred throughout the food through conduction, while liquids do so through convection.
3 0
3 years ago
A river flows due east with a speed of 3.00 m/s relative to earth. The river is 80.0 m wide. A woman starts at the southern bank
babymother [125]

Answer:

48 m

Explanation:

As she travels at the rate of 5m/s due north, the amount of time it would take for her to cross the 80m wide river would be

t = 80 / 5 = 16 seconds

This is also the time it takes for the river to push her to the east side at the rate of 3m/s. So after 16 seconds, she would reach the opposite point at a horizontal distance from her starting of

s = 16*3 = 48 m

4 0
3 years ago
A force of 6600 N is exerted on a piston that has an area of 0.010 m2
sveticcg [70]

Answer:

Choice A: approximately 0.015\; \rm m^2, assuming that the two pistons are connected via some confined liquid to form a simple machine.

Explanation:

Assume that the two pistons are connected via some liquid that is confined. Pressure from the first piston:

\displaystyle P_1 = \frac{F_1}{A_1} = \frac{6.600\times 10^3\; \rm N}{1.0\times 10^{-2}\; \rm m^{2}} = 6.6\times 10^{5}\; \rm N \cdot m^{-2}.

By Pascal's Principle, because the first piston exerted a pressure of 6.6\times 10^{5}\; \rm N \cdot m^{-2} on the liquid, the liquid will now exert the same amount of pressure on the walls of the container.

Assume that the second piston is part of that wall. The pressure on the second piston will also be 6.6\times 10^{5}\; \rm N \cdot m^{-2}. In other words:

P_2 = P_1 = 6.6\times 10^{5}\; \rm N \cdot m^{-2}.

To achieve a force of 9.900 \times 10^3\; \rm N, the surface area of the second piston should be:

\displaystyle A_2 = \frac{F_2}{P_2} = \frac{9.900\times 10^{3}\; \rm N}{6.6\times 10^5\; \rm N \cdot m^{-2}} \approx 0.015\; \rm m^{2}.

4 0
3 years ago
A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, wha
lord [1]

Answer:

The value is F_f =  46.935 \  N

Explanation:

From the question we are told that

    The  magnitude of the horizontal force is F  =  92.7 \  N

     The mass of the crate is  m  =  40.5 \  kg

     The acceleration of the crate is  a =  1.13 \ m/s

Generally the net force acting on the crate is mathematically represented as

       F_{net} =  F -  F_f =  ma

Here F_f is force of kinetic friction (in N) acting on the crate

      So  

            92.7  -  F_f =  40.5 * 1.13

=>         F_f =  46.935 \  N

5 0
3 years ago
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