All categories

3 years ago

Separating paper from a mixture by burning it is it a physical change true or false

Physics

1 answer:

Oduvanchick [21]3 years ago

7 0

Answer:

false

Explanation:

burning something is a chemical change

You might be interested in

A concave spherical mirror has a radius of curvature of magnitude 20.0 cm. (a) Find the location of the image for object distanc

Tems11 [23]

Answer:

Answered

Explanation:

The radius of curvature of the mirror R = 20 cm

then the focal length f = R/2 = 10 cm

(a) From mirror formula

1/f = 1/di + /1do

then the image distance

di = fd_o / d_o - f

= (10)(40) / 40-10

= 30.76 cm

since the image distance is positive so the image is real

ii) when the object distance d_0=20 cm

di = 10×20/ 20-10

= 20

Hence, the image must be real

iii)when the object distance d_0 = 10

di = 10×10 / 10-10 = ∞ (infinite)

the image will be formed at ∞

here also image will be real but diminished.

7 0

3 years ago

Read 2 more answers

True Or False: people in the U.S. consume more liters of water than those in developing nations.

Andru [333]

Truee hope this helps

7 0

3 years ago

Which statement best explains the importance of resource economics?

aleksley [76]

Answer:

it sets consistent prices to achieve sustainability

7 0

2 years ago

A football punter accelerates a football from rest to a speed of 15 m/s during the time in which his toe is in contact with the

ioda

Answer:

Force, F = 44 N

Explanation:

Given that,

Initial speed of the football, u = 0

Final speed, v = 15 m/s

The time of contact of the ball, t = 0.15 s

The mass of football, m = 0.44 kg

We need to find the average force exerted on the ball. It is given by the formula as :

$F=ma\\\\F=\dfrac{mv}{t}\\\\F=\dfrac{0.44\times 15}{0.15}\\\\F=44\ N$

So, the average force exerted on the ball is 44 N. Hence, this is the required solution.

6 0

2 years ago

Calculate the net force on particle q1.

antoniya [11.8K]

By applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.

<h3>Distance between q₂ and q₃</h3>

The distance between the second charge and the third charge is given as;

r = 0.3 m

<h3>Force on q₂ due to q₃</h3>

$F_{2} = \frac{kq_2q_3}{r^2} \\\\F_{2}= \frac{(8.99\times10^9) (7.7 \times 10^{-6})(5.9\times 10^{-6}) }{0.3^2} \\\\F_2 = 4.54\ N$

<h3>Net force on particle q₁</h3>

The net force on particle q₁ is determined by summing the individual forces together;

F(net) = F₁ + F₂

F(net) = -14.4 + 4.54

F(net) = -9.86 N

Thus, by applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.

Learn more about Coulomb's law here: brainly.com/question/24743340

7 0

2 years ago