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const2013 [10]
3 years ago
9

Not a quiz just need help​

Mathematics
1 answer:
tangare [24]3 years ago
3 0
The answer would be-2 and 5
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Find the vertex of the function h(x) = x2 – 4x – 21
lakkis [162]

Answer: (2, -25)

Step-by-step explanation:

The x coordinate of the vertex is x=-\frac{-4}{2(1)}=2.

When x=2, h(2)=2^2 - 4(2)-21=-25.

So, the vertex is (2, -25).

7 0
2 years ago
D over 3.5 minus 13 is greater than -17. Solve for D
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What results only in horizontal compression of y=1/x by a factor of 6
murzikaleks [220]

I'm assuming you mean a compression of factor 6 

In that case, it will be h = 1/6x

4 0
4 years ago
Read 2 more answers
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FromTheMoon [43]

La respuesta es d. Momentum

4 0
3 years ago
An object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seco
bulgar [2K]

Answer:

y=2\text{cos}((\frac{2\pi}{3})t)

Step-by-step explanation:

We have been given that an object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seconds. We are asked to find the cosine function that can be used to model the height of the object.

We know that standard form of cosine function is y = A\cdot \text{cos}(Bt-C)+D, where,

|A| = Amplitude,

Period = \frac{2\pi}{|B|},

C = Phase shift,

D = Vertical shift.

Since distance between maximum and minimum is 4, therefore, amplitude will be half of it, that is, A = 2.

Since objects gets back to its maximum value in every 3 seconds, therefore, period of the function is 3 seconds. We know that period is given by \frac{2\pi}{|B|}, therefore, we can write \frac{2\pi}{|B|}=3, therefore, B = \frac{2\pi}{3}.

We haven't been given any information about phase and mid-line, we can assume the values of C and D to be zero .

Therefore, our function required function would be y=2\text{cos}((\frac{2\pi}{3})t).

6 0
4 years ago
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