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Fittoniya [83]
4 years ago
5

X-intercept=-2, y-intercept = 5

Mathematics
2 answers:
Gre4nikov [31]4 years ago
8 0

I'm assuming you want the equation of a line that cross these points; in that case we have the points :

(-2,0) and (0,5)

The equation of a line is y=mx+b where;

m=slope

and b= y-int

The slope can be found by doing (y(2)-y(1))/(x(2)-x(1)) ... (5-0)/(0--2)... 5/2

m= 5/2 and y-int=5

equation is: y=(5/2)x+5

SVEN [57.7K]4 years ago
7 0

that doesnt make senese


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The solution is x = 2 \text{ and } y = \frac{1}{2}

<em><u>Solution:</u></em>

Let us assume,

a = \frac{1}{x}\\\\b = \frac{1}{y}

<em><u>Given system of equations are:</u></em>

\frac{2}{x} - \frac{3}{y} = -5

\frac{4}{x} + \frac{6}{y} = 14

<em><u>Rewrite the equation using "a" and "b"</u></em>

2a - 3b = -5 ------------ eqn 1

4a + 6b = 14 -------------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 2</u></em>

2(2a - 3b = -5)

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<em><u>Add eqn 2 and eqn 3</u></em>

4a + 6b = 14

4a - 6b = -10

( - ) --------------------

8a = 4

a = \frac{4}{8}\\\\a = \frac{1}{2}

Substitute a = 1/2 in eqn 1

2(\frac{1}{2}) -3b = -5\\\\1 - 3b = -5\\\\3b = 6\\\\b = 2

Now let us go back to our assumed values

Substitute a = 1/2 in assumed values

a = \frac{1}{x}\\\\\frac{1}{2} = \frac{1}{x}\\\\x = 2

Substitute b = 2 in assumed value

b = \frac{1}{y}\\\\2 = \frac{1}{y}\\\\y = \frac{1}{2}

Thus the solution is x = 2 \text{ and } y = \frac{1}{2}

3 0
3 years ago
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