You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
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Hope this is right.
1. 7(4x-5)
2. 28x-35
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Rectangle.
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The 2 dimensional section would be a rectangle.
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In vertex form, the parabola's equation is y=(x−1)^2 +5.
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