3 years ago

GNRJGWUAU HELLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PLease explain ALsssooooOOoo

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

4 0

Answer:

$110 \degree = (4t + 90) \\ 4t = 20 \\ t = 5$

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consider the polynomial 2/3x (2x-3) - (x-7) (x+7) when simplified, what is the coefficent of the quadratic term?

Svet_ta [14]

Answer:

x^2 - 6x + 147 so the coefficient is 1

Step-by-step explanation:

First, simplify the equation.

1. 2/3x(2x-3) = (2x/3)(2x-3)-(x-7)(x+7)

2. 2x-3(2x/3) = (2x(2x-3)) - (x-7)(x+7)

3. Expand -(x-7)(x+7) = -x^2+49

Combine to get (x^2 - 6x)/3 +49

Simplify to get x^2 - 6x + 147. The coefficient of the quadratic term is one.

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3 years ago

Can someone help me out :P

ladessa [460]

Answer:

Step-by-step explanation:

i think it is c bec 1ft is 6m

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3 years ago

The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and

Scorpion4ik [409]

Answer:

$\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)$

Step-by-step explanation:

The PDF of X is

$\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)$

The PDF of Y is

$\bf g(x)=\mu e^{-\mu x}\;(x\geq0)$

The means of X and Y are respectively,

$\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}$

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

$\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)$

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3 years ago

Evaluate the function graphically. Find f(-3)

guapka [62]

Answer:

12x

Step-by-step explanation:

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3 years ago

Simplify. (4w + 3) – 2w + 7 2w + 10 2w - 10 6w + 10 6w - 10

7nadin3 [17]

Hey there,

2w+10 would be the best choice here.
Sorry if I'm wrong, good luck!

:)

3 0

3 years ago