Y= a(x-3)^2+6
2= a(0-3)^2+6
2=a(-3)^2+6
2=a(9)+6
2-6=9a
-4=9a
-4/9=a
Therefore the equation in vertex form is
y = -4/9 (x-3)^2+6
The class has 28 student. One group has four more students so surat 4 from 28. 28-4=24 since one of the groups have twice as many students as the other divide 24 by 3. 24 / 3 = 8. It says 1 group has for more than twice the other group so that would mean 2/3 of 24 and 4 would be the answer 16+4=20. The first group had 8 students, the other group has 20 students.
this can be solve using the formulaP = rghwhere P is the total pressurer is the densityh is the heightg is the acceleration due to gravity
fist solve the total pressureP = 1.5 bar + 1 barP = 2.5 barP = 250,000 Pa
P = rgh250,000 = (997)(9.81)hh =25.56 m
