1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir79 [104]
2 years ago
14

A(n) __________ is a federal program that states are required to implement, but given no additional funds for.

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
5 0

Answer:

<em>It's</em><em> </em><em>answer</em><em> </em><em>is</em><em>:</em><em>-</em>

<em>d</em><em>.</em><em> </em><em>unfunded</em><em> </em><em>mandate</em>

<em>hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em>

You might be interested in
How many times does 0.2 go into 10.88?<br><br> first one to get answer gets 100 ponts
vlada-n [284]

Answer: 54.40

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A concert hall has three sections: the main floor, the balcony, and the gallery. For a recent concert, 1020 tickets were sold. T
Angelina_Jolie [31]

Answer:

Let the number of balcony seats be b

Let the number of gallery tickets be g

Let the number of main floor tickets be m

b + g + m  = 1020

b = 2g

m = b + 225

The number of balcony tickets = 318

The number of gallery tickets = 159

The number of main floor tickets = 543

Step-by-step explanation:

Let the number of balcony seats be b

Let the number of gallery tickets be g

Let the number of main floor tickets be m

i) Therefore we can write b + g + m  = 1020

ii) there were twice as many balcony tickets sold as gallery tickets

   therefore b = 2g      \Rightarrow  g = 0.5b

iii) there were 225 more main floor tickets than balcony tickets

   therefore m = b + 225

iv) using equation ii) and equation iii) in equation i) we can write

     b + g  + m = b + 0.5b + b + 225  = 1020      \Rightarrow 2.5b  = 795     \Rightarrow  b = 318

v) g  = 0.5 b  = 0.5 \times 318 = 159

vi) m = b + 225 = 318 + 225 = 543

5 0
4 years ago
Read 2 more answers
Please help with the question below
lora16 [44]

Considering the unit circle, it is found that the sine is negative on the third and on the fourth quadrant.

<h3>What is the unit circle?</h3>

For an angle \theta the unit circle is a circle with radius 1 containing the following set of points: (\cos{\theta}, \sin{\theta}).

Hence, from the above explanation, the sine is negative when y is negativem, which is on the third and on the fourth quadrant.

More can be learned about the unit circle at brainly.com/question/16852127

#SPJ1

4 0
1 year ago
The Rivertown city council is attempting to choose one of four sites (A, B, C, or D) as the location for its new emergency facil
Vikki [24]

Answer:

SITE A

Step-by-step explanation:

Given :

proposed-site Area-Served

1 2 3 4

A 5.2 4.4 3.6 6.5

B 6.0 7.4 3.4 4.0

C 5.8 5.9 5.9 5.8

D 4.3 4.8 6.5 5.1

Area 1 2 3 4

Number-runs 150 65 175 92

Computing the weighted average for the 4 sites :

Site A:

((150*5.2) + (65*4.4) + (175*3.6) + (92*6.5)) / (150 + 65 + 175 + 92)

= 2294 / 482

= 4.7593

Site B:

((150*6.0) + (65*7.4) + (175*3.4) + (92*4.0)) / (150 + 65 + 175 + 92)

= 2344/ 482

= 4.863

Site C:

((150*5.8) + (65*5.9) + (175*5.9) + (92*5.8)) / (150 + 65 + 175 + 92)

= 2819.6/ 482

= 5.850

Site D:

((150*4.3) + (65*4.8) + (175*6.5) + (92*5.1)) / (150 + 65 + 175 + 92)

= 2563.7/ 482

= 5.319

From the weighted average response time computed for the different sites ;

The best location for the emergency facility would be one with the least average response time; which is SITE A.

7 0
3 years ago
Two automobiles leave the same city simultaneously and both head towards another city. The speed of one is 10 km/hour greater th
Veronika [31]

Answer:

5091 Km/hr and 505 km/hr

Step-by-step explanation:

Speed = Distance / Time

Let the speed of first automobile be 'x' and that of the second be 'y'

Since speed of one is 10 times greater than the other. therefore;

⇒ x = 10 y

also let time for faster automobile be 'T' and time for slower auto mobile be 't'

Since first arrive one hour earlier than second, therefore;

⇒ t = T + 1

⇒ For first automobile; x X T = 560 ; substituting for 'x' and 'T'. Therefore;

⇒ 10y (t+1) = 560

⇒ For Second automobile; y X t = 560

⇒ y = \frac{560}{t}

⇒ 10(\frac{560}{t})(t + 1) = 560

⇒ 5600 + \frac{5600}{t} = 560

⇒ 5600 - 560 =  -  \frac{5600}{t}

⇒ t = 1.11 hr

also ; T = 1.11 - 1 = 0.11 hr

Speed of 1st auto  = 560/0.11 = 5091 km /hr

Speed of 2nd auto = 560/1.11 = 505 km/hr

8 0
3 years ago
Other questions:
  • Evaluate the expression. [3(15 + 4)^2 + 2(20 + 5)^2]^0 A) 0 B) 1 C) 2 D) 5
    14·1 answer
  • HELP needed!!<br>Completely the steps to find the value of x in the angle?​
    12·1 answer
  • Please simplify:<br> 35-[x+7]<br> cause i don't get it.
    15·2 answers
  • Find the distance between the two points in simplest radical form <br> (4,6) and (-2,9)
    9·1 answer
  • Whats the answer 5h-8=2h+19 equality
    15·1 answer
  • The vertices of Figure ABCD are A(1, 1), B(2, 3), C(4, 3), and D(5, 1). If Figure ABCD is reflected over the line y = –1, find t
    7·1 answer
  • 2. The ratio of
    10·1 answer
  • Please please help please please ASAP please I'm begging you please I have 10 minutes please y'all help please any ACE that can
    5·2 answers
  • Which table shows a proportional relationship?
    11·2 answers
  • What is one of the best methods to multiply these binomials: (x+8)(x+7)
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!