Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Answer:
wergi;bwfvhisbohouwdfkwv
Step-by-step explanation:
Hello there! We are given the following equation and want to simplify it:

First, let's use the Distributive Property:
For this step, we are going to let:
After applying this version of the Distributive Property, we are given the equation:

We're going to use the distributive party again, but a slightly different version that's almost the same as first:
Using this on both terms of the equation changes the equation to:

Now, we just remove the parenthesis and combine like terms

This should be your answer. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
w = s/atm
Step-by-step explanation:
I hope this helps,
Please give brainliest