Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
tv-sets are rated by the screen size and the screen size comes from the length of its diagonal.
so a 57" TV has a 57" diagonal.
Check the picture below.
![\bf \stackrel{length}{4\left( \cfrac{57}{5} \right)}\implies \cfrac{228}{5}\implies 45\frac{3}{5}~\hfill \stackrel{width}{3\left( \cfrac{57}{5} \right)}\implies \cfrac{171}{5}\implies 34\frac{1}{5} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Area}{\cfrac{228}{5}\cdot \cfrac{171}{5}}\implies \cfrac{38988}{25}\implies 1559\frac{13}{25}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Blength%7D%7B4%5Cleft%28%20%5Ccfrac%7B57%7D%7B5%7D%20%5Cright%29%7D%5Cimplies%20%5Ccfrac%7B228%7D%7B5%7D%5Cimplies%2045%5Cfrac%7B3%7D%7B5%7D~%5Chfill%20%5Cstackrel%7Bwidth%7D%7B3%5Cleft%28%20%5Ccfrac%7B57%7D%7B5%7D%20%5Cright%29%7D%5Cimplies%20%5Ccfrac%7B171%7D%7B5%7D%5Cimplies%2034%5Cfrac%7B1%7D%7B5%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7BArea%7D%7B%5Ccfrac%7B228%7D%7B5%7D%5Ccdot%20%5Ccfrac%7B171%7D%7B5%7D%7D%5Cimplies%20%5Ccfrac%7B38988%7D%7B25%7D%5Cimplies%201559%5Cfrac%7B13%7D%7B25%7D)
Answer:
−0.965925826289068
Step-by-step explanation:
sin 255 = −0.965925826289068
Answer:
b
Step-by-step explanation: