You may suppose you have a 0.1 M solution of NH3, from:
NH4Cl + NaOH > NH3 + H2O.
Then you can compute the pH from the concentration of NH3 and its pKb.
The concentration is high enough to use the simplified formula:
[OH] = sqr(Kb*conc)
Weight of Chloroform : = 2.862 kg
<h3>Further explanation</h3>
Given
Density 1.483 g/ml
Volume = 1.93 L
Required
Weight of Chloroform
Solution
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:

ρ = density
m = mass
v = volume
Convert density to kg/L :
=1.483g/ml = 1.483 kg/L
So the weight(mass) :
= ρ x V
= 1.483 kg/L x 1.93 L
= 2.862 kg
Answer:
0.382g
Explanation:
Step 1: Write the reduction half-reaction
Al³⁺(aq) + 3 e⁻ ⇒ Al(s)
Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s
We will use the following relationships.
- 1 mole of electrons has a charge of 96486 C (Faraday's constant)
- 1 mole of Al is produced when 3 moles of electrons pass through the cell.
- The molar mass of Al is 26.98 g/mol.
The mass of Al produced is:

Answer:
An ionic bond is an attraction between ions of opposite charge in an ionic compound.
<span>There are 1000 cm3 in 1 liters.
Hence 1 liter of the liquid would weigh:
1000 cm3 x (1.17 g/cm3) = 1170 gm
and there are 1000 gm in 1 kg, so we want enough liters to have a mass of
3.75 kg x 1000 gm/kg = 3750 gm
Hence, # of liters = desired mass / # of gm per liter
= 3750 gm / 1170 gm/liter
= 3.2051282 liters</span>