1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
8090 [49]
3 years ago
14

A flask of fixed volume contains 1.0 mole of gaseous carbon dioxide and 88 g of solid carbon dioxide. The original pressure and

temperature in the flask is 1.0 atm and 300. K. All of the solid carbon dioxide sublimes. The final pressure in the flask is 2.5 atm. What is the final temperature? Assume the solid carbon dioxide takes up negligible volume.
A. 150 K
B. 200 K
C. 250 K
D. 300 K
E. 400 K
Chemistry
1 answer:
lianna [129]3 years ago
6 0

Answer:

The correct option is: C. 250 K

Explanation:

Given: <em><u>Before Sublimation-</u></em>

Initial Temperature: T₁ = 300 K, Initial Pressure: P₁ = 1 atm, Initial number of moles of gas: n₁ = 1 mol, given mass of solid Carbon dioxide: w = 88 g    

<u><em>After Sublimation- </em></u>      

Final Pressure: P₂ = 2.5 atm, Final number of moles of gas: n₂ = ? mol

Final Temperature: T₂ = ? K,            

Also, Volume is constant, Molar mass of Carbon dioxide: m = 44 g/mol

As we know,

<em>The number of moles:</em>

n = \frac {given\: mass\: (w)} {Molar\: mass\: (m)}

<em>So the number of moles of carbon dioxide sublimed:</em>

n = \frac {w}{m} = \frac {88\: g} {44\: g/mol} = 2 mol

<em><u>Therefore, the final number of moles of gas after sublimation:</u></em>

n_{2} = n_{1} + n = 1\: mol + 2\: mol = 3\: mol

<u><em>According to the </em></u><u><em>Ideal gas equation</em></u><u><em>:</em></u>

P.V = n.R.T

or, \frac {P_{1}.V_{1}}{n_{1}.T_{1}} = \frac {P_{2}.V_{2}}{n_{2}.T_{2}} \: \: \: \: \: \: ....equation\: (1)

<em>Since the volume is constant, so the equation (1) can be written as:</em>

\frac {P_{1}}{n_{1}.T_{1}} = \frac {P_{2}}{n_{2}.T_{2}}

\Rightarrow \frac {1\:atm}{1\:mol \times 300\:K} = \frac {2.5\:atm}{3\:mol \times T_{2}}

\therefore T_{2} = \frac {2.5\:atm \times 300\:K \times 1\:mol}{3\:mol \times 1\:atm}

\Rightarrow T_{2} = 250\:K

<u>Therefore, the final temperature: T₂ = 250 K</u>

You might be interested in
If 45.0 mL of ethanol (density = 0.789 g/mL) initially at 8.0 ∘C is mixed with 45.0 mL of water (density = 1.0 g/mL) initially a
strojnjashka [21]

Answer : The final temperature of the mixture is, 22.14^oC

Explanation :

First we have to calculate the mass of ethanol and water.

\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 45.0mL=35.5g

and,

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ethanol = 2.42J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ethanol = 35.5 g

m_2 = mass of water = 45.0 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of ethanol = 8.0^oC

T_2 = initial temperature of water = 28.6^oC

Now put all the given values in the above formula, we get:

35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC

T_f=22.14^oC

Therefore, the final temperature of the mixture is, 22.14^oC

3 0
3 years ago
How is a mixture such as a plate of pasta different from a mixture such as air
stealth61 [152]

Answer:

Well there is a lot of differences between the two. Its called homogeneous and Heterogeneous mixtures. Homogeneous mixtures are all the substances are evenly distributed throughout the mixture (salt water, air, blood).  Heterogeneous mixtures are the substances that are not evenly distributed (chocolate chip cookies, pizza, rocks). So Pasta with sauce and meatballs is heterogeneous and air is homogeneous




HOPE THIS HELPS HAVE A GREAT DAY!!~

Explanation:

6 0
2 years ago
How would you separate the following ions by selective precipitation Ag + , Pb 2+, Cu 2+.​
Lemur [1.5K]

Answer:

we cannot vduurggruuriirru**

4 0
2 years ago
Prove how the Law Conservation of Mass and Enery apply to Cellular Respiration​
snow_lady [41]

Answer:

mass and energy is reused when those things happen

7 0
3 years ago
Usually , it takes very little time for a community to develop during primary succession False True
Arte-miy333 [17]
False! Primary succession is when a community has to completely start over which takes a long time.
6 0
2 years ago
Other questions:
  • Which of the following is an anion?<br> A. O2- <br> B. Mg2+ <br> C. Al3+ <br> D. H
    10·1 answer
  • Consider the equation below. CaCO3(s) &lt;—&gt;CaO(s) + CO2(g) what is the equilibrium constant expression for the given reactio
    15·2 answers
  • Which of the following could be the name of the substance in box ‘c` choose only one box:
    8·2 answers
  • A substance whose water solution is a good conductor of electricity is an ________
    11·1 answer
  • What best explains the type of energy present in the vibrating atoms of a substance
    5·1 answer
  • What value must be known if the accuracy of an experiment is to be determined​
    13·1 answer
  • Consider the balanced equation below.
    12·2 answers
  • 4. The [H+] in solution is 1.0 X 10-3 M. This solution is BEST classified as?
    7·2 answers
  • What is the answer to-6 + 1 = -5/
    7·1 answer
  • Which formula can be used to calculate the percent yield?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!