If further increases in substrate concentration do not result in further increases in reaction rate, then an enzyme is likely

1 answer:

4 0

Given what we know, we can confirm that if further increases in substrate concentration do not result in further increases in reaction rate, then an enzyme is likely saturated.

<h3>What does it mean for an enzyme to be saturated?</h3>

Enzymes work by binding to the substrate in specific zones of the enzyme. The zones are known as the active sites on enzymes. Since enzymes have a limited amount of these zones, once they are all bonded to a substrate, we can say that it is saturated.

Therefore, the saturation of enzymes allows us to explain how further increases in substrate concentration do not result in further increases in reaction rate.

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If you have 3.0 moles of argon gas at STP, how much volume will the argon take up?

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3 years ago

Balance the following redox reaction by inserting the appropriate coefficients. SO4^2- + NH3 = SO3^2- + H2O + N2

Harlamova29_29 [7]

SO₄²⁻ +NH₃ → SO₃²⁻ + H₂O +N₂

The balanced of the above redox reaction is as below

3SO₄²⁻ + 2NH₃ → 3SO₃²⁻ + 3 H₂O + N₂

Explanation

According to the law of mass conservation the number of atoms in the reactant side must be equal to number of atoms in product side.

Inserting coefficient 3 in front of SO₄² , 2 in front of NH₃, 3 in front of SO₃²⁻ and 3 in front of H₂O balance the equation above. This is because the number of atoms are equal in both side.

for example there are 2 atoms of N in both side of the reaction.

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2 years ago

Read 2 more answers

H3PO4 + Ca(OH)2 → Ca(H2PO4)2 + H2O

aniked [119]

Given question is incomplete. The complete question is as follows.

Balance the following equation:

$H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O$

Answer: The balanced chemical equation is as follows.

$2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O$

Explanation:

When a chemical equation contains same number of atoms on both reactant and product side then this equation is known as balanced equation.

For example, $H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O$

Number of atoms on reactant side:

H = 5

P = 1

O = 6

Ca = 1

Number of atoms on product side:

H = 6

P = 2

O = 9

Ca = 1

In order to balance this equation, we will multiply $H_3PO_4$ by 2 on reactant side and we will multiply $H_2O$ by 2 on product side. Hence, the balanced chemical equation is as follows.