A line passing through the points (6,-2) and (-2,4). Complete the work shown

Mathematics

1 answer:

Marrrta [24]3 years ago

3 0

Answer:

2.5

Step-by-step explanation:

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Match the sequences with the type of sequence (arithmetic or geometric).

Anni [7]

9, 4, -1, -7
Arithmetic because it has a common difference of 5.

4, 10, 16, 22
Arithmetic because it has a common difference of 6.

2, -6, 18, -54
Geometric because it has a common ratio of -3.

4, 4, 4, 4
Both because it has a common difference of 0 and a common ratio of 1.

Hope this helps :)

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3 years ago

For problems 1–3, identify the terms, coefficients, constants, and factors of the given expressions.

Volgvan

Answer:

1 4 ^2 + 2 - 9

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2 years ago

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The length of a rectangle is represented by the function L(x) = 5x. The width of that same rectangle is represented by the funct

IgorC [24]

A= l x w
5x * 2x^2 - 4x + 13
10x^3 - 20x^2 + 65x

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3 years ago

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Following are heights, in inches, for a sample of college basketball players. 78 83 82 78 78 80 81 79 79 83 77 78 84 82 80 80 82

blagie [28]

The mean height of the basketball players is 80.3 inches

For given question,

we have been given the list of heights, in inches, for a sample of college basketball players.

We need to find the mean height of the basketball players.

We know that, for given sample of data

mean = sum of all observations ÷ total number of observation

First we find the sum of given heights.

78 + 83 + 82 + 78 + 78 + 80+ 81 +79+ 79 +83+ 77 +78+ 84+ 82+ 80+ 80 +82+ 84+78+ 80 = 1606

Total number of observations = 20

Using the formula of mean,

⇒ mean height = 1606/20

⇒ mean height = 80.3 inches

Therefore, the mean height of the basketball players is 80.3 inches

Learn more about the mean here:

brainly.com/question/6813742

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1 year ago

The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given

slavikrds [6]

Answer:

a) $\frac{dm}{dt} = -k\cdot m$ , b) $m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ , c) $m(t) = 10\cdot e^{-\frac{t}{2438.155} }$ , d) $m(300) \approx 8.842\,g$