A line passing through the points (6,-2) and (-2,4). Complete the work shown

Find the equation of the line that is perpendicular to the line x = −5 and passes through the point (1, π). A) y = π B) y = πx C

Leviafan [203]

Answer:

Step-by-step explanation:

$\text{The equation of a horizontal line:}\ y=a.\\\\\text{The equation of a vertical line:}\ x=a\\\\a-any\ real\ number\\\\\text{We have}\ x=-5.\ \text{It's a vertical line.}\ \text{The line that is perpendicular}\\\text{to the vertical line is a horizontal line.}\\\\\text{The line passes through the point}\ (1,\ \pi)\to x=1,\ y=\pi.\\\\\text{Therefore the equation is}\ y=\pi$

5 0

3 years ago

Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

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11 3/4 x 15 3/4 ?????????

Novay_Z [31]

Answer:

185 1/16

Step-by-step explanation:

3 0

2 years ago

Which ordered pair is the solution to the system of linear equations y = -7x + 2 and y = 9x - 14?

lisabon 2012 [21]

Y = -7x + 2
y = 9x - 14

-7x + 2 = 9x - 14
14 + 2 = 9x + 7x
16 = 16x
1 = x

y = -7x + 2
y = -7(1) + 2
y = -7 + 2
y = -5

solution is : (1,-5) <==

4 0

2 years ago

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Which line segment is drawn in the figure? A.YZ B.WY C.XZ D.WZ

Dima020 [189]

The line segment shown in the figure is C. XZ. A line segment is a line that is bounded by 2 endpoints, hence the line is not infinite. As shown in the figure, only points X and Z are visibly connected. There are no visible lines connecting the other points together.

6 0

3 years ago

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