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3 years ago

HELPPP Solve for b 2 in A = h(b 1+b 2), if A = 16, h = 4, and b 1 = 3. b 2 =

Mathematics

2 answers:

Lilit [14]3 years ago

6 0

Answer:1

Step-by-step explanation: substitute all the corresponding terms so you get, 16=4(3+b2)

Then you multiply and get 16=12+4b2 then subtract 12 from both sides to get 4=4b2 and then divided both sides by 4 and you get 1=b2

Shkiper50 [21]3 years ago

5 0

Answer:1

Step-by-step explanation: A = h(b 1+b 2)

16=4(3+b2)

16/4=3+b2

4=3+b2

B2 =4-3=1

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Please help me complete this !! 12points

Svet_ta [14]

Answer:

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

x1=0

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y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

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x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

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Jet001 [13]

So, the area of a parallelogram is the base times the height or

$a = b \times h$

a being area

b being base

h being height

the height is 8 cm and the base is 15 cm

(remember: the heght should be perpendicular to the base)

so we plug in 8 for h and 15 for b to get

$a = 15 \times 8$

and 15 × 8 = (10 × 8) + (5 × 8) = 80 + 40 =120

So the answer is 120

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miskamm [114]

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Tiana is on a 25-foot ladder that is leaning against her house. Its base is 7 feet from the base of the house. The ladder slips

Lostsunrise [7]

Answer:

4 ft downwards

Step-by-step explanation:

old height off the ground :

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7+8=15

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