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2 years ago

5. Each polygon circumscribes a circle. Find the perimeter.

Mathematics

1 answer:

Oksana_A [137]2 years ago

6 0

See the diagram of the circumscribed polygon attached below:

Answer:

A. 14.2 in.

Step-by-step explanation:

Perimeter = 3.7 + 3.6 + 3.4 + 1.9 + g

Let's find g.

a = 1.9 in. (Tangents drawn from an external point of a circle are congruent)

b = 3.4 - 1.9 = 1.5 in.

b = c = 1.5 in. (Tangents drawn from an external point)

d = 3.6 - 1.5 = 2.1 in.

d = e = 2.1 in. (Tangents drawn from an external point)

f = 3.7 - 2.1 = 1.6 in.

f = g = 1.6 in. (Tangents drawn from an external point)

✔️Therefore,

Perimeter = 3.7 + 3.6 + 3.4 + 1.9 + 1.6 = 14.2 in.

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35 rounded to the nearest hundred

Volgvan

Answer and Explanation: 35 rounded to the nearest 100 is 0. To round to the nearest hundred, you need to first identify the hundreds that are closest to the number you are rounding. For 35, the closest hundred that is lower than 35 is 0, and the closest 100 that is higher than 35 is 100.

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2 years ago

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2 years ago

The base of a triangle is 4 meters shorter than the height. What are the height and length of the triangle if its area is 48 squ

Sergeeva-Olga [200]

Answer: H=12 and B=8

Looking at the problem, you are given the area, a , and told the h is 4 meters longer than b; in other words, h=b+4.

Since a=1/2bh, you can replace a with 48. Also, since h is b+4, you can replace that as well. You'd end up with this equation:

48=1/2b(b+4)

1. Seeing that 48 is 1/2 of b, you know that you have twice the value of 48, or 96. So, you can put that 96=b(b+4).

2. Now, thinking through factors of 96- 1 x 96, 2 x 48, 3 x 32, 4 x 24, 6 x 16, or 8 x 12, the only pair in which h is b+4 is 12 x 8.

Hope this helps,

Lacia :))

8 0

2 years ago

Consider the initial value function y given by

Nuetrik [128]

Answer:

y(s) = $\frac{5s-53}{s^{2} - 10s + 26}$

we will compare the denominator to the form $(s-a)^{2} +\beta ^{2}$

$s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$

comparing coefficients of terms in s

$s^{2} :$ 1

s: -2a = -10

a = -2/-10

a = 1/5

constant: $a^{2}+\beta ^{2} = 26$

$(\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09$

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = $A(s-a)+B((s-a)^{2} +\beta ^{2} )$

we insert the values of a and β

$\\5s-53$ = $A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )$

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

the constants are

a = 0.2

β = 5.09

A = 5.4

B = -2

Step-by-step explanation:

since the denominator has a complex root we compare with the standard form $s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$
Expand and compare coefficients to obtain the values of a and β as shown above
substitute the values gotten into the function
Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

3 0

2 years ago

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$

3 0

2 years ago