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3 years ago

5. Each polygon circumscribes a circle. Find the perimeter.

Mathematics

1 answer:

Oksana_A [137]3 years ago

6 0

See the diagram of the circumscribed polygon attached below:

Answer:

A. 14.2 in.

Step-by-step explanation:

Perimeter = 3.7 + 3.6 + 3.4 + 1.9 + g

Let's find g.

a = 1.9 in. (Tangents drawn from an external point of a circle are congruent)

b = 3.4 - 1.9 = 1.5 in.

b = c = 1.5 in. (Tangents drawn from an external point)

d = 3.6 - 1.5 = 2.1 in.

d = e = 2.1 in. (Tangents drawn from an external point)

f = 3.7 - 2.1 = 1.6 in.

f = g = 1.6 in. (Tangents drawn from an external point)

✔️Therefore,

Perimeter = 3.7 + 3.6 + 3.4 + 1.9 + 1.6 = 14.2 in.

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A survey showed that 77% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 22 adults are

Sveta_85 [38]

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

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Step-by-step explanation:

A survey showed that 77% of adults need correction for their eyesight.

If 22 adults are randomly selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find $P(x\leq 11)$

$P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)$

Formula : $P(x=r)=^nC_r p^r q^{n-r}$

$P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}$

Using calculator

$P(x\leq 11)=0.00512$

So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

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