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3 years ago

5. Each polygon circumscribes a circle. Find the perimeter.

Mathematics

1 answer:

Oksana_A [137]3 years ago

6 0

See the diagram of the circumscribed polygon attached below:

Answer:

A. 14.2 in.

Step-by-step explanation:

Perimeter = 3.7 + 3.6 + 3.4 + 1.9 + g

Let's find g.

a = 1.9 in. (Tangents drawn from an external point of a circle are congruent)

b = 3.4 - 1.9 = 1.5 in.

b = c = 1.5 in. (Tangents drawn from an external point)

d = 3.6 - 1.5 = 2.1 in.

d = e = 2.1 in. (Tangents drawn from an external point)

f = 3.7 - 2.1 = 1.6 in.

f = g = 1.6 in. (Tangents drawn from an external point)

✔️Therefore,

Perimeter = 3.7 + 3.6 + 3.4 + 1.9 + 1.6 = 14.2 in.

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Explain how to determine the zeros of f(x)= (x+3)(x-2)(x-6)

Deffense [45]

Answer:

The zeros of f(x) are -3, 2 , 6

Step-by-step explanation:

f(x) is a polynomial of degree 3.

If the polynomial is not factorized we will either factorize to find the zero or use trial and error method.

Since the f(x) in the question is in the factorized form. we will have to equate each factor to zero.

f(x) = (x+3)(x-2)(x-6)

x + 3 = 0 => x = -3

x - 2 = 0 => x = 2

x - 6 = 0 => x = 6

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2 years ago

lawyer [7]

Answer - A

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3 years ago

Read 2 more answers

Please use the following image in order to answer the question correctly:

andriy [413]

Answer:

134 degrees.

Step-by-step explanation:

This is a simple one.

The arc RS subtends an angle of 67 degrees on the circumference,

So the measure of the arc RS is 2 * 67 = 134 degrees.

3 0

3 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary).

Virty [35]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{9})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(1-3)^2+(9-6)^2}\implies d=\sqrt{(-2)^2+3^2} \\\\\\ d=\sqrt{13}\implies d\approx 3.6056\implies \stackrel{\textit{rounded up}}{d=3.6}$

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3 years ago

The sum of three consecutive integers is greater than 66. What is the smallest possible product of the largest and smallest of t

AysviL [449]

Answer:

528

Step-by-step explanation:

So naturally at first sight for this question we would think -->

Oh 3 consecutive integers = 66 --> 66/3 = 22 (n-1), (n+1) so --> 21, 22, and 23.

But no. At second look it is the sum of 3 consecutive integers is greater than 66. So we find the next possible pair since it says smallest possible product.

We get the set (22, 23, 24). => Multiply the least and greatest integers together respectively 22 and 24 which amounts to => 528

And thus, we have out answer of 528

Hope this helps!

4 0

3 years ago