Answer:
triangle
Step-by-step explanation:
A triangle can not have 2 right angles.
I am pretty sure the answer is 3.5.
(2+x)5=11
(2+x)=11/5
(2+x)= 5.5
x= 5.5-2
x= 3.5
Another way to do it is
2x-y=17
x-y=10, x=10+y
substitute x=10+y for x in 2x-y=17 and get
2(10+y)-y=17
20+2y-y=17
20+y=17
subtract 20 from both sides
y=-3
subsitute y=-3 into equation x-y=10
x-(-3)=10
x+3=10
subtract 3 from both sides
x=7
or subsitute into 2x-y=17
2x-(-3)=17
2x+3=17
subtract 3 from both sides
2x=14
divide both sides by two
x=7
Answer:
C. 150
Step-by-step explanation:
It's right on Plato.
If we try to evaluate this expression, we arrive at an indeterminate limit of the form ∞ · 0. So we rewrite this limit as
lim of [ e^(-x/5) / (1 / x^3) ] as x→∞
This results in an determinate form of 0/0, so we apply L'Hospital's rule by differentiating the numerator and denominator.
lim of [ -1/5e^(-x/5) / (-3/x^4) ] as x→∞
Multiply the numerator and denominator by x^4
lim of [ -1/5 * x^4 * e^(-x/5) / (-3) ] as x→∞
Since e^(-x/5) approaches 0 as x→∞, the limit evaluates to 0.
The answer to this question is 0.