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Answer:
30.1 feet.
Step-by-step explanation:
We have been given that a school flag poll casts a 16 foot shadow on the lawn. A teacher stood at the shadows edge and measure the angle of elevation to the top of the poll at 62°. We are asked to find the height of the tall.
First of all, we will draw a diagram to represent our give scenario as shown in the attachment.
We can see that side length with 16 feet is adjacent side and height of the pole (h) is opposite side to angle of elevation.
We know that tangent relates opposite side of a right triangle to its adjacent side.
Therefore, the poll is approximately 30.1 feet tall.
Answer:
No student liked only Nokia
Step-by-step explanation:
The information can be illustrated as shown on the Venn diagram.
The number of students who liked only Nokia is x.
The sum of all regions in the Venn diagram should be 40.
We add all to get:
Therefore no one liked only Nokia
The height of the smaller building is <u>94.63 feet</u>, computed using the trigonometric ratios.
In the question, we take AB to be the taller building, where A is its top and B is its base, CD to be the shorter building, where C is its top and D is its base, and CE to be the perpendicular from C to AB.
Given that the horizontal distance between the two buildings is 260 feet, we can say that BC = CE = 260 feet.
The angle of elevation from the top of the shorter building to the top of the taller building is 30°, that is, ∠ECA = 30°.
The angle of depression from the top of the shorter building to the base of the taller building is 20°, that is, ∠ECB = 20°.
When ∠ECB = 20°, then ∠CBD = 20°, as they are alternate angles.
We are asked to find the height of the shorter building, that is, we are asked to find CD.
In ΔCBD,
tan ∠CBD = CD/BD {perpendicular/base},
or, tan 20° = CD/260,
or, CD = 260*tan 20° = 260*0.36397023426 {∵ tan 20° = 0.36397023426},
or, CD = 94.6322609092.
Therefore, the height of the smaller building is <u>94.63 feet</u>, computed using the trigonometric ratios.
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