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Mamont248 [21]
3 years ago
12

Pls help ill give brainliest

Mathematics
1 answer:
ki77a [65]3 years ago
7 0
The answer would be:

3q x (2q + 1) x (q^2 - 4)

Hope this helped :)
You might be interested in
Question
Cerrena [4.2K]

Answer:C(x) = 2000+ 0.05 x

Step-by-step explanation: Cost (C) = fixed cost + (cost per pencil x number of pencils)

Since:

Fixed cost: $2000

Cost per pencil : $0.05

Replacing with the values given:

C(x) = 2000+ 0.05 x

Where x is the number of pencils manufactured.

Feel free to ask for more if needed or if you did not understand something.

6 0
1 year ago
Find the sum of the mixed number 4 7/8 + 7 5/8
Fofino [41]

Answer:

61/ 4

(Decimal: 15.25)

Step-by-step explanation:

47 /8  +  75 /8

= 47/ 8 +  75/ 8

=  47+75 /8

=  122 /8

=  61/ 4

(Decimal: 15.25)

5 0
3 years ago
Compute the following 5/9+1/4
n200080 [17]

Answer:

29/36

Step-by-step explanation:

5/9 + 1/4

The common denominator is 36

5/9 *4/4 = 20/36

1/4*9/9 = 9/36

20/36 + 9/36 = 29/36

3 0
3 years ago
Read 2 more answers
What is the value of 5 in 756? Write and draw to explain how you know.
fomenos
The value of 5 into 756 is .0066, or 0.66%. You can write this out as shown, and draw it out using traditional division.
5 0
3 years ago
Need help asap important! thanks so much!
a_sh-v [17]

Answer:

You would have $343.37 at the end of the 2 years.

Step-by-step explanation:

Interest earned is like bonus money the bank pays you just for keeping money

\mathrm{Compund\:Interest\:Formula}:\quad A =  P {  \left( 1+ \dfrac{ r  }{ n  }    \right)    }^{ nt  }

P: the starting balance of the account (also called initial deposit, or principal)

A: the new balance in the account after N years.

t: the number of years or time

r: the interest rate, (in decimal form)

n: the number of times the interest is compounded each year.

Annually = each year = 1

P =$300, r = 7%, t = 2, n = 1, A = ?

Substitute the numbers into the "Compound Interest Formula".

A =  300 {  \left( 1+ \dfrac{ 0.07  }{ 1  }    \right)    }^{ 1 \times  2  }

\mathrm{Anything\:divided\:by\:1\:gives\:itself}

A =  300 {  \left( 1+0.07  \right)    }^{ 1 \times  2  }

\mathrm{Add\:1\:and\:0.07\:to\:get\:1.07}

A =  300 \times   { 1.07  }^{ 1 \times  2  }

\mathrm{Multiply\:1\:and\:2\:to\:get\:2}

A =  300 \times   { 1.07  }^{ 2  }

\mathrm{Calculate\:1.07\:to\:the\:power\:of\:2\:and\:get\:1.1449}

A =  300 \times  1.1449

\mathrm{Multiply\:300\:and\:1.1449\:to\:get\:343.47}

A =  343.47

So you would have $343.37 at the end of the 2 years.

Look at the chart

\mathrm{Year}\quad \mathrm{Year\: Interest}\quad \mathrm{Total\:Interest}\quad \mathrm{Balance}\\\quad1\quad\quad\quad $21.00\quad\quad\quad\quad $21.00\quad\quad\quad\quad $321.00\\\quad2\quad\quad\quad $22.47\quad\quad\quad\quad $43.47\quad\quad\quad\quad $343.47

8 0
3 years ago
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