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3 years ago

Two charges of magnitude ‒Q and +4Q are located as in the figure below. At which position (A, B,

Physics

1 answer:

NeTakaya3 years ago

6 0

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Can the tangent line to a velocity vs. time graph ever be vertical? Explain.

34kurt

Answer:

No. Because it would correspond to zero Instantaneous acceleration.

Explanation:

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3 years ago

What force controls the isostatic adjustment of Earth’s crust?

Alina [70]

The force that control the isostatic adjustment of the earth's crust is THE FORCE OF GRAVITY.
The isostatic adjustment of the earth crust refers to continuous movement of the earth crust or its deformation as a result of the force of gravity which act on it. The earth crusts that are located at the upper and a the core of the earth usually set up a balance between them which is called isostatic equilibrium.

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3 years ago

Read 2 more answers

Suppose that a parallel-plate capacitor has circular plates with radius R = 25 mm and a plate separation of 4.7 mm. Suppose also

ozzi

Answer:

a) $B_{max} = 1.784*10^{-12}$

Explanation:

Given paraeters are:

R = 25 cm

d = 4.7 mm

f = 60 Hz

$V_m$ = 160 V

a) $V = V_msin(2\pi ft)$

Where $f = 60$ Hz and $V_m = 160$ V

$E =V/d= \frac{V_msin(2\pi ft)}{d}$

For $r = R$

$A = \pi R^2$

Since $\Phi_E = EA$

$\Phi_E=\frac{\pi R^2V_msin(2\pi ft) }{d}$

From Ampere's Law:

$\int B.ds = \mu_0\epsilon_0\frac{d\Phi_E}{dt} + \mu_0I_{encl}$ where $I_{encl}=0$

So at $r = R$ ,

$B.2\pi R = \mu_0\epsilon_0\frac{d\Phi_E}{dt}\\B.2\pi R = \mu_0\epsilon_0\frac{2\pi^2fR^2V_mcos(2\pi ft)}{d}\\B = \frac{\mu_0\epsilon_0\pi fRV_mcos(2\pi ft)}{d}$