All categories

1 year ago

What is 6,210 bucks converted to kilobucks?

2 answers:

8 0

6,210/1000=6.21

Kilo means thousand so each kilobuck has a thousand bucks. Divide 6210 (number of bucks) by 1000 (number of bucks in a kilobuck) to find your answer.

Vinvika [58]1 year ago

4 0

When 6210 bucks is converted to kilobucks, the result obtained is 6.21 kilobucks

<h3>Conversion scale </h3>

1000 bucks = 1 Kilobuck

Using the above convesion scale, we can express 6210 bucks in kilobucks

<h3>How to express bucks in kilobucks</h3>

1000 bucks = 1 Kilobuck

Therefore,

6210 bucks = (6210 × 1) / 1000

6210 bucks = 6.21 kilobucks

Thus, 6210 bucks is equivalent to 6.21 kilobucks

Learn more about conversion:

brainly.com/question/2139943

You might be interested in

A 1.2 KG rubber ball is being thrown in the air if the ball is traveling at 2.0 M/S when it is 3.0 M off the ground what is the

Vitek1552 [10]

Answer:

37.7 J

Hope this helps! (see pictures)

6 0

2 years ago

Which clue indicates that a speciation has occurred between two populations?

Diano4ka-milaya [45]

I believe the answer is C

4 0

2 years ago

Light travels at the same speed at all times. True False

topjm [15]

Answer:

true hope this help :}

Explanation:

6 0

2 years ago

Read 2 more answers

A very long uniform line of charge has charge per unit length λ1 = 4.68 μC/m and lies along the x-axis. A second long uniform li

Kitty [74]

Answer:

$E_{net} = 6.44 \times 10^5 N/C$

Explanation:

As we know that electric field due to infinite line charge distribution at some distance from it is given as

$E = \frac{2k \lambda}{r}$

now we need to find the electric field at mid point of two wires

So here we need to add the field due to two wires as they are oppositely charged

Now we will have

$E_{net} = \frac{2k\lambda_1}{r} + \frac{2k\lambda_2}{r}$

now plug in all data

$\lambda_1 = 4.68 \muC/m$

$\lambda_2 = 2.48 \mu C/m$

$r = 0.200 m$

now we have

$E_{net} = \frac{2k}{r}(4.68 + 2.48)$

$E_{net} = \frac{2(9\times 10^9)}{0.200}(7.16 \times 10^{-6})$

$E_{net} = 6.44 \times 10^5 N/C$

8 0

2 years ago

The vehicles are fitted with shockers why

MissTica

Shockers acts as a shock absorber in the vehicle making the ride comfortable. When vehicle goes on rough road then it gets shocks from the road deformities the springs present in the shockers provide counter force and thus making the vehicle stable ride without shock.

[I copied this from the internet, but hope it helps!]

7 0

2 years ago